I'd like some help! Thank you

Question

+1

53

1

+46

The product of four consecutive positive integers is $1$ less than $461^2$ . What is the least of these four numbers?

I've tried writing equations but that didn't work. Can someone help? Thank you!

greenplanet2050 · Answer 1 · 2024-02-29T05:37:34

Actually, I solved it! If anyone needs help? Here a hint: Use difference of squares: $x^2-y^2=(x+y)(x-y)$ and prime factorization!