+0  
 
+1
30
1
avatar+46 

The product of four consecutive positive integers is \(1\) less than \(461^2\). What is the least of these four numbers?

 

I've tried writing equations but that didn't work. Can someone help? Thank you! smiley

 Feb 29, 2024
 #1
avatar+46 
0

Actually, I solved it! If anyone needs help? Here a hint: Use difference of squares: \(x^2-y^2=(x+y)(x-y)\) and prime factorization! smiley

 Feb 29, 2024

0 Online Users