GYanggg

You can draw a venn diagram for this.

Since there are x Spanish students and y French students, there are x + y total students. 

But since there are repeats that we counted twice, we subtract the repeating numbers so we only count it once. 

\(x + y - z \) is your final answer.

i hope this helped, 

Gavin. 

The only digit we have restictions for is the last one, it must be even.

The other digits in the number ABCDE have no restrictions and can be any one of the 5.

There are only two even numbers in the list, so there are 2 choices for the last digit.

The other 4 digits have no restrictions, and since the problem allows repeats, there are 5 choices.

The final answer is:

\(5^4\cdot2=\boxed{625}.\)

I hope this helped. 

Gavin

Hey guest. 

We first need to find about how many numbers between 2001 and 2999 are divisible by 4.

The largest number between these two values that is still divisible by 4, is 2996.

The largest number between these two values that is still divisible by 4, is 2004. 

To find out how many numbers are divisible by 4, we do:

\((2996-2004)\div4+1=249\)

Now we need to see how many of these numbers are divisible by 100. 

From 2001 to 2999, we have:

2100, 2200, 2300, 2400, 2500, 2600, 2700, 2800, and 2900

Now we need to see how many of these numbers are divisible by 400.

We have:

2400, 2800

Finally, we have:

\(249-9+2=242\)

The answer you seek is 242.

i hope this helped, 

Gavin.

I hope this helped.

It is an equation, 0.27 =  26/YX

you multiply both sides by YX

0.27 * YX = 26

YX is about 96.

What do you not understand.

To solve YZ, you use tangent. 

Tangent is opposite over adjacent.

Tan 28 = 26/ YZ

you can solve for YZ

64. 

You tangent for 64.

sin 28 = 26 / YX

sin 28 is about 0.27

0.27 = 26/YX

you can solve for YX

I do not think that is the correct answer.

The two RQ are not equal.

Or maybe the fraction sign looks like a 1 :)

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