GYanggg

Alright, he you go: 

Using the rule,

a + b > c

Where a, b, and c are any of the three sides of a triangle, we have three inequalities. 

5 + 8 > x 

5 + x > 8

8 + x > 5

The first one is x < 13

The second one is x > 3

The third one is x > -3

So the interval of x is 3 < x < 13

Assuming that the question is asking for the possible integer, we have: 

4, 5, 6, 7, 8, 9, 10, 11, and 12.

We first need to rationalize the denominator of the left side of the equation. 

We we can multiply both the numerator and the denominator by $sqrt{32}$.

We have $\dfrac{4\sqrt{2}}{96}=2n$

After dividing both sides by 2, we have n = sqrt2/48

All students.

Hello! 

The teacher her should definitely use a computer to randomly select 30 student IDs from all 

students because it is more random and we can have a more accurate and reliable data set. 

She shouldn’t select the people in the chess club because they obviously all play chess.

Using a computer to just select students from just her students is not broad enough.

Selecting every other student also provides an inaccurate data set because it depends on who sits next to who. 

I hope this helps. 

Here we go:

Which undergoes HA<=> H+ + A- 
ka = [H][A] / [HA] 
you know [H+], but what are the others? 
Write the electroneutrality equation for the entire reaction (including water's dissociation) 
[H+] = [OH-] + [A-] ....we know that [H]>>>[OH], so 
[H+] = [A-] 
next write the total concentration equation (mass balance equation) 
Ct = 0.5M = [A-] + [HA] 
[HA] = 0.5 - [A-] = 0.5 - [H+] 

all together you have: 
ka = [H]^2 / (0.5 - [H+]) 
ka = 0.0001*0.0001/(0.5-0.0001) = 2.00x10^-8 

Hope you can understand this approach

HA<=> H+ + A- 
ka = [H][A] / [HA] 
you know [H+], but what are the others? 
Write the electroneutrality equation for the entire reaction (including water's dissociation) 
[H+] = [OH-] + [A-] ....we know that [H]>>>[OH], so 
[H+] = [A-] 
next write the total concentration equation (mass balance equation) 
Ct = 0.5M = [A-] + [HA] 
[HA] = 0.5 - [A-] = 0.5 - [H+] 

all together you have: 
ka = [H]^2 / (0.5 - [H+]) 
ka = 0.0001*0.0001/(0.5-0.0001) = 2.00x10^-8 

I hope this helps!

B

88 / (17 + 88 + 25 + 57) = 0.4705882353...

Round to the nearest whole percent, we have 0.47 or 47%.

The answer would be B. 

Hey Chris!

Just a quick question, if I do the problem, I will probably hard expand it, but is there are better way that just isolates the constant?

A way that doesn't require you to expand the whole expression?

The two factors of the first number that you are looking for is 11 and 5.

We first prime factorize 55, and we get 5 * 11.

So we can immediately test 5 and 11.

5 * 11 = 55 and 5 + 11 = 16.

it works!

i hope this helped.

Here you go:

 ∠ R = α = 28.072° = 28°4'21″ = 0.49 rad

This is a trigonometry problem. We have to use inverse oprations.

We can use any of the sine, cosine, tangent, cotangent, secant, and cosecant since we know all of the 3 sides.

Let's just say we use sine. 

It is basically the ratio of the side opposite to the angle to the hypotenuse.

In this case, it is 8 : 17. 

The inverse of sine of 8/17 is 49 rad or about 28 degrees.

I hope this helps.