Jamesaiden

$\angle N=\angle O=90$

$\angle J+\angle H=360-\angle O-\angle N=360-90-90=180$

I'm not sure about this

(2x - 30) + x = 180

3x = 210

x = 70

arc CB = 2x - 30 = 140 - 30 = 110

$4125=3\times 5^3\times 11$ first 3 multiple of 5 : 5,10,15

m = 15

$2816000=2^{11}\times 5^3\times 11$ multiple of 2 : $2, 2^2, 2\times 3, 2^3, 2\times 5, 2^2\times 3, 2\times 7$

n=15

n - m = 15 - 15 = 0

9z + 7 + 74 = 180

9z = 99

z = 11

$\angle A+\angle C=180$

$\angle A+101=180$

$\angle A=79$

$\angle B+\angle D=180$

$\angle B+68=180$

$\angle B=112$

(4n - 2) + (3n + 8) = 180 - 90

7n + 6 = 90

7n = 84

n = 12

(2y + 1) + (5y - 3) = 180

7y - 2 = 180

7y = 182

y = 26

volume = $(6\times 3\times 1)+(4\times 3\times 8)=18+96=114ft^3$

Volume = $\frac{1}{3}\times (4\times 10)\times 6=2\times 40=80 cm^3$

$300=2^2\times 3\times 5^2$

Because A the product of the divisors of 300 who only have this 3 distinct prime divisors, so there are 3 distinct prime divisors from A.