In triangle ABC, let angle bisectors BD and CE intersect at I. The line through I parallel to BC intersects AB and AC at M and N, respectively. If AB = 17, AC = 24, and BC = 33, then find the perimeter of triangle AMN.
The perimeter of triangle AMN works out to 45.
Sorry thats wrong
The answer is 41, and the proof is ridiculously easy when you see it. No cosine rule or trig ratios needed.
Thanks! Thats correct
+150 
