Jasino

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Let $ABC$ be a triangle. Let $X$ be a point on $\overline{AC}$ such that $\angle BXA = 90^\circ.$ If $\angle ABC = 90^\circ,$ $AX = 15,$ and $CX = 6,$ then what is $BX?$

Jasino 2 hours ago

+6

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Nevermind, I figured it out myself, the answer is:

3sqrt(10)

Jasino1 hour ago