2.499999997e10=2.499999997*10^10=24999999970
3(q+8.3g)=67.5g
Divide 3 to both sides
q+8.3g=22.5g
Subtract 8.3 to both sides
q=14.2g
(x^2/2)*6x^3
=3x^5
I put the numbers in 'Mach Equation' from WolframAlpha.
tan A=2/3, tan B=-3/5
A=33.69, B=30.96
So the value of cot 2.73 is 20.97158
The square root of ten is approximately 3.1622776602.
6/x=y-19
Add 19 to both sides
y=6/x+19
So the answer is (-6,18), (-3,17), (-2,16), (-1,13), (1,25), (2,22), (3,21), (6,20)
A jet traveling through 10 degrees Celsius at mach 3
Speed:1012m/s
27=-3x-9
Add 9 to both sides
-3x=36
Divide -3 to both sides
x=-12
Click on the right side of the caculator bar where it says 'Scientific' and click 'Fractions'.
