jugoslav

The drawing is not to scale.

the length is 7.5m

dimensions of the base (and the top) are:  4m, 5m, √41m 

Given a trapezium with two parallel sides of lengths m and n, where m and n are integers, prove that it is possible to divide the trapezium into several congruent triangles.

a)   Surface area is:  A = (54 * 2) + (36 * 24) = 972 cm² = 0.0972 m²

b)   Possible dimensions of the sides are:     9, 12, 15     (9+12+15=36) (9² + 12² = 15²)

This is the wrong link.

https://web2.0calc.com/questions/pls-help-due-tmrow_9

I was using my own diagram.

I'll give you my 3-step solution without using anyone's diagram.

1/    ∠DAQ ≅ ∠BAP = arctan(DQ / AD) = 26.56505118º

2/    ∠PAQ = 90º - (∠DAQ + ∠BAP) = 36.86989765º

3/     sin(∠PAQ) = 0.6    or   3/5  

It's trivial enough, is it not? 

(calculator: 0.5 => inv => tan => * 2 => -90 => + => sin => 0.6 )