+0  
 
0
30
4
avatar

Let X, Y, and Z be points on a circle. Let XY and the tangent to the circle at Z intersect at W. If WX = 4, WZ = 8, and WY is perpendicular to WZ, then find YZ. 

*PS - The answer is not 4 * sqrt(29)*

 Oct 16, 2020
 #1
avatar
0

By power of a point, YZ = 3*sqrt(7).

 
 Oct 16, 2020
 #2
avatar+240 
0

https://web2.0calc.com/questions/pls-help-due-tmrow_9

 
 Oct 16, 2020
 #4
avatar+240 
0

This is the wrong link.laugh

 
jugoslav  Oct 16, 2020
 #3
avatar
0

Important:  If one secant and one tangent are drawn to a circle from one exterior point, then the square of the length of the tangent is equal to the product of the external secant segment and the total length of the secant:

 

Knowing this, we have:

 

WZ2 = WX * WY              82 = 4 ( 4 + XY )           XY = 12

 

YZ = sqrt ( WZ2 + WY2 ) = √320 smiley

 
 Oct 16, 2020

38 Online Users