ABCD is a parallelogram. E is a point on AB such that AE:EB = 1:2, F is the mid-point of CD. AF meets DE at G and BF meets CE at H. When expanded on both sides, GH meets AD at M and BC at N. If the area of ABCD is 420, find the sum of the areas of the triangles ∆CNH and ∆DGM.
The sum of the areas of the triangles ∆CNH and ∆DGM is 48 u2