jugoslav

Let a side of a hexagon be equal to the height (or length) of a solid.

Solid A          A = 28 cm²

I'm gonna use this formula to calculate a² ( and b²)

2(3√3*a²/2) + 6a² = 28         a² = 2.5008485          a = 1.581407127

V_(A) = 3√3/2 * a = 10.27502675 cm³ 

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Solid B          A = 40.32 cm²

2(3√3*b²/2) + 6b² = 40.32         b² = 3.601221843         b = 1.897688553

V_(B) = 3√3/2 * b = 17.75524625 cm³

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V_(B)  :  6912  =  V_(A)  :  x

x = 4000 grams  

Really? If you can do more then 3, I'll give you 2 ++

Only four integers can be used: 2, 3, 4 and 5

1st  Δ    2, 5, 5

2nd Δ    3, 4, 5

3rd Δ    4, 4, 4

y = (5/7) (3-1) + 1 = 2.428571429

Hint: to calculate the third side, use the law of cosines and quadratic equation.

To find the angle you're looking for, use the law of cosines.

Good luck!

urw, keep doing a good job.

16x - 4 = 2*6x

16x - 4 = 12x

4x = 4

x = 1

FH = 2*6x = 12

sin A = sin(90º) = 1 

hint:     Use sine for y and cosine for x

Yes, this is called: Intersecting chords theorem. (Wikipedia has a solid explanation of this theorem)

Since the diameter is the longest chord of a circle, it's included in this theorem.

Good job, asinus!