Consider a square ABCD with side length 2. Let E be the midpoint of AB, F the midpoint of BC, and P and Q the points at which line segment AF intersects DE and DB, respectively. What is the area of EBQP?
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I'll borrow Phill's diagram.
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Area of Δ ABD = 2
Since DE is a median of Δ ABD, the area of Δ BED = 1
∠ADE = tan-1(1/2)
DP = cos-1(∠ADE) * 2
∠EDB = 45 - ∠ADE
PQ = tan(∠EDB) * DP
Area of Δ DPQ = 1/2 (DP * PQ)
[EBQP] = [EDB] - [DPQ] = 7/15 or 0.466666667 square units