In the figure, if \(FR = FG\), the measure of arc \(FG\) is \(130^\circ\), and measure of arc \(FQ\) is \(28^\circ\), then what is \(\angle RPG\), in degrees?
Angle RPG = (130 + 28)/2 = 79 degrees.
Arc RG = 100º ∠GFR = 1/2 * 100 = 50º
Arc FQ = 28º ∠FGQ = 1/2 * 28 = 14º
∠FPG = 180 - (50 + 14) = 116º
∠RPG = 180 - ∠FPG = 64º
or
∠RPG = (arc GR + arc FQ) / 2
∠RPG = (100º + 28º) / 2 = 64º
thank you so much! :))
