jugoslav

Your x coordinate is off!!!

x = 27/8 

[ABC] = 1.5        [ADN] = 1.5

EN = (1.5 * 2) / 4 = 0.75

MF = ((3 - 0.75)/2) + 0.75 = 1.875

DF = 1/3(1.875) = 0.625

AF = AD - DF = 3.375

Coordinates  M (3 ³/₈, 1 ⁷/₈ )        ( M is the midpoint on the line segment CN)

Two angles of a triangle measure 30 and 45 degrees. If the side of the triangle opposite the 30-degree angle measures 6√2 units, what is the sum of the lengths of the two remaining sides? Express your answer as a decimal to the nearest tenth.

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∠A = 30º        ∠B = 45º         ∠C = 180 - 30 - 45 = 105º

a = 6√2

a/b = sin∠A / sin∠B             b = 6√2 * sin45º / sin30º         b = 12

a/c = sin∠A / sin∠C             c = 6√2 * sin105º / sin 30º       c ≈ 16.4

b + c ≈ 28.4          (This answer is ≈ correct)

Pleeeeease, don't post this question again. 

https://web2.0calc.com/questions/urgent-help-needed_6

https://web2.0calc.com/questions/trapezoid_25#r3

Hahahaha...

x = 1/2(-7 +(-1))             y = 1/2(-9 +(-1))    

Good job, Guest!!!

(13 + x)/2 *18 = 152.1

x = 3.9

So, the other base is 3.9 km long. 

Since I cannot edit my post, I have to repost it.

Someone's playing games with me; the base CD was 38 and now is 32. 

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AB = 25       CD = 32

MN = 57        MO = 25          MR = 28.5            OR = 3.5 

XY = OR = 3.5     

As shown in the diagram, PQ is the median of trapezoid ABCD where AB = 25 inches and CD = 32 inches. Find XY in inches.

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I find CPhill's method to be very clever, so I'll use and simplify this method even more.

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AB = 25          CD = 38                  

MN = 63        MO = 25         MR = 31.5        NO = 38        OR = 6.5        AM = 12.5

Important: Triangles ABO and OXY are similar.

Eureka!   If AB = MO then XY = OR

XY = 6.5 inches