+230 Two angles of a triangle measure 30 and 45 degrees. If the side of the triangle opposite the 30-degree angle measures $6\sqrt2$ units, what is the sum of the lengths of the two remaining sides? Express your answer as a decimal to the nearest tenth.
+1641 Two angles of a triangle measure 30 and 45 degrees. If the side of the triangle opposite the 30-degree angle measures 6√2 units, what is the sum of the lengths of the two remaining sides? Express your answer as a decimal to the nearest tenth.
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∠A = 30º ∠B = 45º ∠C = 180 - 30 - 45 = 105º
a = 6√2
a/b = sin∠A / sin∠B b = 6√2 * sin45º / sin30º b = 12
a/c = sin∠A / sin∠C c = 6√2 * sin105º / sin 30º c ≈ 16.4
b + c ≈ 28.4 (This answer is ≈ correct
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Pleeeeease, don't post this question again. 
