Thank you so much.
in lowest terms where the top and thee bottom share no common factors so it cannot be simplified any further.
SO would that simplify to \(p(x+y+z)+q(x+y+z)+r(x+y+z)=1+x+y+z\)
How do you know
OK Thank you for the confermation
NVM Thank you soo much melody I understand it now and the answer is 1
How did you find that
Thanks Melody I appreciate it and it makes way more sense now
Thanks Melody youre the best
Ok Everyone that has looked at this the answer is on the original
Melody I found one of the originals it is https://web2.0calc.com/questions/an-advanced-quadratics-problem however it is wrong but I don't see what went wrong in the work.