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liemJR
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liemJR
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f(x) = x^4 - 4x^2 - 3 is concave down on the interval I = (Approximate your answer to 3 decimal places.)
f(x) = x^4 - 4x^2 - 3 is concave down on the interval I = (Approximate your answer to 3 decimal places.)
CPhill
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liemJR
Oct 27, 2014