$${\mathtt{121}}{\mathtt{\,\times\,}}{\mathtt{121}} = {\mathtt{14\,641}}$$
Since theirs different types of A does that mean AABBB and AABBB could be different.
AABBB
ABBBA
BBBAA
BABAB
BAABB
BABBA
ABABB
ABBAB
BBABA
um... >.<
5!/(2!×3!)
1*2*3*4*5=120
1*2=2
1*2*3=6
is it 120 divided by 6 * 2 ? $${\frac{{\mathtt{120}}}{\left({\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{2}}\right)}} = {\mathtt{10}}$$
how would "!" be written on paper?
A1 A2 B1 B2 B3
5 letters
2A
3B
so
5!/(2!*3!) ?
That many possibilities?! O.O
since it's 9!/(2!*3!) if i was to simplify it into one number. I thought it'll be 15 ? But it seems to small so for each letter? 15*9=135
But then 15 seems so small.
Is it 15 per letter. So 15*9=135
Sorry for all the Q.'s :(
So altogether there would be 15?
2: 1*2 (2 options)
3: 1*2*3 (3 options)
9: 9*8*7*6*5*4*3*2*1 (9 options)
9+3+2=15? Sorry I'm not familiar with this working but I hope I'm getting it.
Also, thanks for the support it's much appreciated.
:)
Cool, thanks.
I understand now.
But " 9!/(2!*3!)" means= 9*2*3
???
Thanks
PS. ^ he was me
Wow!
I'm still puzzled at Q.2 though...
>.<
So 5 drinks and 3 cakes would be the answer?
