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92-29=63

92

The length of that type of diagonal is sqrt3 times the side length. So the rectangle would be \(x\sqrt{3}\) times \(x\) or \(x^2\sqrt{3}\)

The area of a hexagon is \((3\sqrt{3})*x^2/2\). What we have is \(x^2\sqrt{3}\). So multiply that by 3/2 to get 40*3/2=60

1.

Say the second piece is length x. The first piece is 3 times that, so it is 3x.

The 3rd piece is 20 feet shorter than it, so it is x-20.

Adding them we get 5x-20, and that equals 100. 

Solving for x we get 24.

So the lengths are 72, 24 and 4.

2.https://www.wyzant.com/resources/answers/739241/algebra-cowboy-problem

3.

Square 1: Side length 11

Square 2: Side length 5

5*4=20

4.https://web2.0calc.com/questions/please-answer-these-asap-thanks

a) 10^999=5^999*2^999

5^999*5^-999*2^999*2^-999=1*1=1

b)

Smallest 2 digits- 18

Smallest 3 digits- 108

Smallest 4 digits- 1008

18+108+1008=1134

c)

2 digits- 16

3 digits- 104

4 digits- 1000

16+104+1000=1120

d) 

2 digit- 14

3 digit- 105

4 digit- 1001

14+105+1001=1120

e)

1, 2, 3, 6, 7

Add them

Largest: 13

Smallest: -1

13-(-1)=14

1. Round them 

10*6*7=420

She has 3/2 kilos left.

Circumference = 2piR

Circumference=30pi

660pi/30pi=22 rotations

gcf(12,8)=4

The largest side possible is 4 feet.

The x^2 doesn't matter (or x for that matter) since it is 1

So we have -2+3i-7-2i+37-13i

Simplifying we get 28-12i