The area of the gray rectangle is 40 m^2. Find the area of the regular hexagon in square meters.
+539 The length of that type of diagonal is sqrt3 times the side length. So the rectangle would be \(x\sqrt{3}\) times \(x\) or \(x^2\sqrt{3}\)
The area of a hexagon is \((3\sqrt{3})*x^2/2\). What we have is \(x^2\sqrt{3}\). So multiply that by 3/2 to get 40*3/2=60
