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MrBigbig
Username
MrBigbig
Score
54
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Questions
0
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27
0 Questions
27 Answers
#1
+54
0
9x + 10 = 11x
2x = 10
x = 5
MrBigbig
Nov 7, 2013
#1
+54
0
x = [12 + ( 144 + 28 )^ 0.5 ]/14
or. [12 - ( 144 + 28 )^ 0.5 ]/14
x = (6 + sqrt(43))/7 or (6-sqrt(43))/7
MrBigbig
Nov 7, 2013
#1
+54
0
ln (5x-6) = ln18 - ln (x-3)
ln (5x-6) = ln (18/(x-3))
5x-6 = 18/(x-3)
(5x-6)(x-3) = 18
5x^2 -21x +18 = 18
x(5x-21) = 0
x = 0 or 21/5
BUT (5x-6) and (x-3) cannot be negative
So x>6/5 and x>3, x>3
So x can only be 21/5.
MrBigbig
Nov 7, 2013
#1
+54
0
0
W = F·S = FScos theta, in this case, theta = 90°
because cos90° = 0, so net work is 0.
MrBigbig
Nov 7, 2013
#1
+54
0
Five thirds
MrBigbig
Nov 6, 2013
#1
+54
0
24hr = 86400s
(86400/6)*5 = 72000 times
MrBigbig
Nov 6, 2013
#1
+54
0
-3x+2y=-6 ---(1)
5x-2y=18-----(2)
(1)+(2)
2x=12 ->x=6
-3(6)+2y=-6
2y=12 -> y=6
So x=y=6
MrBigbig
Nov 6, 2013
#1
+54
0
5x+8
MrBigbig
Nov 6, 2013
#1
+54
0
sin45° = 1/sqrt(2) = 6.81/h
h/6.81 = sqrt(2)
h = 6.81*sqrt(2) = approximately 8.740
MrBigbig
Nov 6, 2013
#4
+54
0
1+(tan theta)^2 = (sec theta)^2
tan theta = 4^2 - 1= 15
tan theta = 15^0.5 or -(15^0.5)
Because it's in the fourth quadrant, so tan theta must be negative
So tan theta = -(15^0.5)
MrBigbig
Nov 6, 2013
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