NinjaAnswer

6/1004---------Divide both numerator and denominator by 2

3/502-----------Answer

Approximately--------0.00597609561

-3x+8 and 5x+10-2-8x

-3x+8

You cant simplify this anymore

5x+10-2-8x

(5x-8x)+(10-2)

-3x+8

They are the same

what is 16⁸ = 2^?

^{We know 2^4 = 16}

^{That means :} 

^{(2)^8*4 = 2^?}

^{2^32 = 2^?}

^{? = 32}

If you want us to prove, then:

sqrt(8^2*7*5^2-175) = 105

sqrt(11200-175) = 105

sqrt(11025) = 105?

Correct

We have to use a little bit of casework to solve this problem. If the first die shows a 1, the second die can be anything (6 cases). If the first die shows 2 or 4, the second die is limited to 1, 3, or 5 (2 * 3 = 6 cases). If the first die shows 3, the second die can be 1, 2, 4, or 5 (4 cases). If the first die shows 5, the second die can be anything but 5 (5 cases). If the first die shows 6, the second die can be only 1 or 5 (2 cases). There are 36 ways to roll two dice, 23 of which are valid, so the answer is 23/36.

Case 1: 1 T 

3 options for where the T is, 4 options for A, R, G or E and 3 for the last slot.

3 * 4 * 3 = 36

Case 2: 2 T's

3 options for non T's and four options for the last slot. 

3 * 4 =  12

Total:

36 + 12 = 48<------------Answer

Cool!!

Might be a ninja meteorologist when I grow up!

There are three ways to draw two blue marbles and a red one: RBB, BRB, and BBR. Since there are no overlapping outcomes, these are distinct cases and their sum is the total probability that two of the three drawn will be blue. The desired probability therefore is

(10/16)(6/15)(5/14) + (6/16)(10/15)(5/14) + (6/16)(5/15)(10/14) = 15/56