NinjaAnswer

I dont think so....

This is false.

(x)^1/3 + (x - 16)^1/3 = (x - 8)^1/3------------Cube each side

3 (x - 16)^(1/3) x^(2/3) + 2 x + 3 (x - 16)^(2/3) x^(1/3) - 16 = x - 8 -------------Isolate all radicals

3 (x - 16)^(1/3) x^(2/3) + 3 (x - 16)^(2/3) x^(1/3) = -x + 8 

idk what to do from here LOL. Thats what we learned in school with square roots. But that is Algebra 2 and this is NOT algebra 2! I am about to go to school and gonna see if my teacher can do it and get back to you.

Slope is (y₂ - y₁)/(x₂ - x₁)

(-2,3) (-4,5)

(5-3)/(-4--2)

2/(-4+2)

2/-2

-1 is the slope

Lol thanks! I actually am 12! I am a boy, by the way. Sorry I couldn't explain. Going back to school tomorrow and had to finish a bunch of stuff. I didn't have enough time. Sorry!

4/9

Thanks CPhill!!

The answer is 11

Equation 1: 3g+24=3(g+8)

3g+24=3(g+8)--------Simplify

3g+24 = 3g + 24------Subtract 3g + 24 from each side(you might relieze that there are infinitly many solutions from this step)

0 = 0 ---------Infinitly many solutions

Equation 2:  5c+9=5c-12

 5c+9=5c-12--------Subtract 5c from each side

9 =-12  ---------------Since 9 doesn't equal -12 then there are no solutions 

Equation 1 has infinitly many solutions

Equation 2 has no solutions

if you mean 5^x = sqrt(5) then:

x = 1/2

Because square roots are numbers raised to the 1/2 power.

Hope that helped