QuestionableBean

We can start by seeing Randy + Raul = 177 and Firmino + Raul = 131. Firmino = $\frac{1}{3}\text{Randy.}$ Raul = 177 - Randy and Raul = 131 - Firmino. Now we have 177 - Randy = 131 - Firmino. Now we can substitute to get 177 - 3(Firmino) = 131 - Firmino, and now 46 = 2 Firmino. Firmino = 23. We can take this and find Raul = 131 - 23 and then Raul = 108. 177 - 108 = 69 cards. Now that Raul = 108 and Randy = 69, we just subtract 69 from 108 to get 39 cards more than Randy.

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CPhill can help!

https://web2.0calc.com/questions/algebra-problem_44

Hope this helped :)

x does not equal 1 or 2 though. I am confused. Can you explain?

Hope this helped :)

I don't quite understand how you got to this? Can you explain?

This questions was answered here:

https://web2.0calc.com/questions/congruence_4

I think any multiple of 7 less than 7 would do the job because there seems to be no negative limit.