SHIHABX

The volume of a sphere = 4/3 * pi * (radius)³

So, the volume of the sphere = 4/3 * pi * 2³

(a)  7y(-4xy + 5) = (7y* -4xy) + (7y*5) = -28xy² + 35y

(b) 7x(-4x + 5y) = (7x* -4x) + (7x*5y) = -28x² + 35xy

(c) 7x(-4y + 5y) = (7x* -4y) + (7xx*5y) = -28xy + 35xy

(d) 7y(-4x + 5) = (7y* -4x) + (7y*5) = -28xy + 35y

So, the bottom-most option is the right answer.

SO, The volume of the figure = (The volume of the larger Rectangular Parallelopiper) + (The volume of the smaller Rectangular Parallelopiper)

We know, the volume of a Rectangular Parallelopiper = a.b.c (where a is length, b is width and c is hight)

So, the volume of the larger Rectangular Parallelopiper = (12*3*8) inch ³ = 288 inch³

and the volume of the smaller Rectangular Parallelopiper = (5*3*5) inch³ = 75 inch³

THE VOLUME OF THE FIGURE IS = (288 +75) inch³ = 363 inch³