Sir-Emo-Chappington

11666666666666666666666

Let's add some commas to make it easier to read... (Or periods in some countries)

11,666,666,666,666,666,666,666

Now, the level of magnitude of the 11 is 10^21, also known as "Sextillion".

So we have:

11 Sextillion, 666 Quintillion, 666 Quadrillion, 666 Trillion, 666 Million, 666 thousand, 6 hundred and 66

or: 

Eleven Sextillion, six hundred and sixty six Quintillion, six hundred and sixty six Quadrillion, six hundred and sixty six Trillion, six hundred and sixty six Million, six hundred and sixty six thousand, six hundred and sixty six.

$${\sqrt{{\mathtt{x}}}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}}}$$

Let's combine the surds. To do this, square one of them (so put it in terms of it's square root)

$${\sqrt{{{\sqrt{{\mathtt{x}}}}}^{\,{\mathtt{2}}}{\mathtt{\,\times\,}}\left({\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}}$$

Now simplify since obviously the square of a square root is...

$${\sqrt{{\mathtt{x}}{\mathtt{\,\times\,}}\left({\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}}$$

Expand out the equation inside the surd and you get:

$${\sqrt{{{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{x}}}}$$

Assuming it is not compound interest (Since if it was, the daily gain would change on a yearly basis):

1 year of interest = 10,000 * 5%

= 10,000 * ¹/₂₀

= ^10,000/₂₀

= 500

1 day of interest = ⁵⁰⁰/₃₆₅

= $1.37

200 * ¹/₄ * ¹/₂ * ¹/₅

= 100 * ¹/₄ * ¹/₅

= 25 * ¹/₅

= 5

Depends how you mean "add".

If you mean something like -7 + 4, then look at which number is larger. The larger number subtracted by the smaller number gives you the resulting value, and if the larger number is the negative one, then the resulting value is negative. so -7 + 4 = - (7  -4) = - (3) = -3

Consider positives as "removing" negative values, and negatives "removing" positive values. It's easier to work this way as long as you identify which value is bigger.

If you mean adding a negative number as though it was a positive number, this is represented as "|x|" meaning you get the value of x in it's positive form (So if x = -8 then |x| = 8, and if x = 4 then |x| = 4).

-3 + -5 + 1

Consider that "+ -" is just another way of saying "minus" or " - " (I actually do this all the time personally. Makes it easier to understand numbers as negatives and not negative as a function).

So we have:

- 3 - 5 + 1

Combine the negatives together:

- 8 + 1

Now combine these two together:

 -7

to type the inverse trigonomic function, enter "a" before it.

This gives "acos", "asin" and "atan" as the invesre functions. (In your case it would be "asin")

Suggest (2x - 3)/(x-2) = 1

2x - 3 = x - 2

2x - x = -2 + 3

x = 1

Suggest (2x - 3)/(x-2) = -1

2x - 3 = -1(x - 2)

2x - 3 = -x + 2

3x = 5

x = 5/3

x = 1

x = 5/3

(6121.23N) / (78.54x10-^6 )

First since we have some scientific notation present, I'll turn this whole thing into scientific notations:

= ([6.12123 * 10³]N) / (7.854 * 10^-5)

Now seperate out the magnitudes and combine them

= [(6.12123 / 7.854) * 10^3--5] N

Complete the fraction

= 0.7793773873185638  * 10⁸ N

And now round it for simplicity and make it comply with Scientific Notation

= 7.794 * 10⁷ N

Alan, that is not fully correct. While atan is the same as "tan^-1()", that "-1" is not actually it's power: it's merely a common notation to mean the inverse function (So if you had "3" instead that would be saying the tangent function 3 times).

Instead, tan to the power of -1 is referred to as "cot()" or "cotangent".

In simpler terms:

Suggest: y = tan(x)

∴ tan^-1(y) = x

∴ y^-1 = cot(x)