SpawnofAngel

31+32+33 = 96

31

One

I did all that work

For

One

Wow

XD I'm 2 grades ahead. It is fine. But make sure to memorize any formulas or methods of doing things. Like the pythagorean Theorem. I'm using that in Pre-Calculus right now

Find X, im assuming?

$2^x*5^{3x} = 4^{2x+1}$

Lets go ahead and take the natural log of each side

$ln{2^x}*ln{5^{3x}} =ln{ 4^{2x+1}}$

Then bring down those exponets and pull out the x's on the left

$x(ln{2}*(3)ln{5}) = (2x+1)*ln{4}$

Pull the X's over to the right and natural log's to the left

$\frac{ln{2}*(3)ln{5}}{ln{4}} = \frac{2x+1}{x}$

Simplify

(ln(2)+3(ln(5)))/ln(4) = 3.98289

(2x+1)/x

You can split these into 2x/x and 1/x

becomes 2+1/x

3.98289 = 2+1/x

1.98289 = 1/x

1.98289x = 1

x = 1/1.98289 = 0.5043

x = .5043

I got 3/169 or B.

I don't know if they are independent or dependent

Help with what?

What equals X?

x = -5 and -9

2^63 = 9,223,372,036,854,775,808

Part A:

6 in chemistry

11 in algebra

6 in both

6+11+6 = 23

 Part B:

2000/40 = 50

12 in chemistry of a sample of 40

12*50 = 600

600 in chemistry of a school of 2000

12/40 = 3/10

When 3 out of every 10 students are in chemistry simply multiply by 200 to find the total students of the school enrolled so that

600/2000 = 3/10

Welp, I had no idea what I was talking about

sin(53)= 125/x

x*sin(53) = 125

x = 125/sin(53)

x = 156.517