Register
Login
Information
This feature requires your approval of cookies
You can approve cookies in the notification bar at the top of this window
Information
This feature requires your approval of cookies
Home
Forum
^{+0}
Widgets
Formulary
Maths
Help
Complex Numbers
Integral Calculus
Differential Calculus
Equations
Graphs
Linear Algebra
Number theory
Percent
Standard Functions
Statistics
Trigonometry
Unit Conversion
Units
About
Imprint
Privacy Policy
Terms of Service
Credits
Google+
Facebook
Contact Email
Yes I am 16 or older
Cookie Consent
I accept third party cookies used to show me
personalized
ads. I also accept that these cookies are used to share information about my use of this site with advertising providers who may combine it with other information that I have provided to them or that they’ve collected from my use of their services.
I accept strictly necessary cookies that guarantee functions without which I could not use this website as intended.
Configure
I accept all cookies
unlimited
sponsored calculations per hour
Stu
Username
Stu
Score
1314
Stats
Questions
73
Answers
292
81 Questions
302 Answers
0
506
1
+1314
Is this image conveying accurately?
is it accurate?
where did the 60 v come from?
do you have to draw on amp leaving battery to be correct? *fig 2.
why when take away the v source, do we leave 28 ohm when it it cannot carry current? is it just that when we cant
read more ..
●
Stu
Oct 26, 2014
0
1404
7
+1314
help with circuits
can anyone make then selc available to call or skype with to assist me with some cir uit fundementals tonight for an exam in the morning?
LancelotLink
●
●
●
●
●
●
●
Stu
Oct 26, 2014
0
742
8
+1314
Mesh/Kirchhoffs theorem.
can someone define the values in the equation one and two stated in the image please.
Alan
●
●
●
●
●
●
●
●
Stu
Oct 7, 2014
«
latest
7
6
..
2
1
»
#1
+1314
+3
.
Stu
Feb 11, 2014
#1
+1314
0
Straight division. Biggest number over smallest number.
Big/Small= That number answer is the exact percent. Round up or down to the nearest. Or to 2 or 3 decimal placings.
What I did... I copied your questions numbers, big and pasted into my calculator online/computer and put the division sign then pasted the smaller number in then hit equals ( = ). You can do it to, or type the numbers in.
Good luck.
Stu
Feb 11, 2014
#1
+1314
0
Here is something to help you apply it.
I'm not upto learning this, and someone will advice you when they're online. But this is a start.
http://web2.0calc.com/questions/viewtopic.php?f=2&t=8599 <-- highlight and right click goto.
There is also calculators for the rules to solve for equilateral, oblique and right angled triangles here:
http://www.mathportal.org/calculators/plane-geometry-calculators/sine-cosine-law-calculator.php
Stu
Feb 11, 2014
#1
+1314
0
[size=150]One of the best![/size]
---------------------------------
Here's one of the first to stop at for PROBLEM SOLVING, SELF TESTS, CALCULATORS AND FOR FORMULAS.
http://www.mathportal.org/ [size=85]<---- highlight and right click goto.[/size]
It is very simply designed with great navigation and excellent very defined search engine. Will fit most needs with all the calculators for maths, and formula you like. The search engine is the most useful tool!
Easy to use for all levels, and on a sliding scale of complexity depending on what you want to achieve. The more complex maths you are looking up, the more that's required to perhaps use the tool you need. ie basic understanding of how to use an online graphing calculator if it's what you want. That shouldn't be out of your reach!
Easy to use input to get output tools- eg, polynomial calculator.. 3 types.. put in your equation and get an answer. It also generates problems! BONUS!
____________
Thanks
Stu,
Learning E&E
Stu
Feb 11, 2014
#2
+1314
0
What she said ^
Stu
Feb 11, 2014
#1
+1314
0
need to add the two together. To do so we add 60 and 2/3 to 5 and 1/2. But to add the fraction component we need the bottom of both to match, finding the lowest common denominator. Also to multiply the top by any multiple of change at the bottom.
ie.
Now the equation is 60 and 4/6 + 5 and 3/6 litres. WE can add them, 60+5 and 4/6 + 3/6 equal to 65 and 7/6 litres. The 7/6th component is also the same as 6/6 + 1/6. the 6/6 is a whole so we have 66 litres and 1/6 total. The 1/6 is 1000/ 6 to find out the value in millilitres. I'l leave that to you.
here is a calculator. Just plug the numbers and same sign in as you would a normal calculator for a straight forward answer..
http://web2.0calc.com/
the lowest common denominator, is the lowest number which is a multiple of both fractions bottoms. When we multiply the bottom on either or both we need to make the top also multiplied by the same amount. Means 3/4 and 4/3 we need 12 on the bootom of both, the 3/4 is multiplied by 3 on the bottom and the 4/3 multiplied by 4 on the bottom so we multiply the top of both respectively as given.
Don''t forget to give your answer in litres.
Good luck.
Stu
Feb 11, 2014
#1
+1314
0
please give more information when you're on about why you need to have this answered and the type of question if a problem or basic maths, for a response. Thanks.
here is a calculator. Just plug the numbers and same sign in as you would a normal calculator for a straight forward answer.. try 3+2= excluding the fact they are apples for the answer.
http://web2.0calc.com/
Good luck.
Stu
Feb 11, 2014
#2
+1314
0
An answer has been given.
please give more information when you're on about why you need to have this answered and the type of question if a problem or basic maths, for a response. Thanks.
here is a calculator. Just plug the numbers and same sign in as you would a normal calculator for a straight forward answer..
http://web2.0calc.com/
Good luck.
Stu
Feb 11, 2014
#1
+1314
+3
An answer has been given.
Please refer to a 1 times table or 3 times table for the answer. This can be found online through any search engine.
here is a calculator. Just plug the numbers and same sign in as you would a normal calculator for a straight forward answer..
http://web2.0calc.com/
Good luck.
Stu
Feb 11, 2014
#2
+1314
0
To op: ie. ORIGINAL POSTER. Try to define your question with words and what you are trying to resolve through asking it. Nobody can read your mind, even if the question in and of itself seems to be explanatory. This is the basics to get the best help possible from the volunteers here.
If you're playing games on the other hand, or making some kind or remarks to your self because you though it wouldn't be answered, or that it's fun to see how one would respond to a brief and common case in maths, then it's been achieved and one would hope in the future you consider maths and the time of those dedicating themselves to the site worth more.
Atm, the forum is knew and establishing. Therefore, if you have serious questions (they'l always be answered which is the goal of the site.)
Try putting the sum/problem with words so the helpers can get an idea.
Stu
Feb 10, 2014
«
latest
29
28
..
2
1
»