y=x3
y2−y=2⇒{y=2y=−1}
x3=2⇒{x=(2(13)×√3×i−2(13))2x=−(2(13)×√3×i+2(13))2x=2(13)}⇒{x=−0.6299605249474366+1.0911236359724287ix=−(0.6299605249474366+1.0911236359724287i)x=1.2599210498948732}
x3=−1⇒{x=−(√3×i−1)2x=(√3×i+1)2x=−1}⇒{x=−(−12+0.866025403785i)x=12+0.866025403785ix=−1}
So the real solutions are:
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