OP = x
OB = OD = OF = R
PB = 9v RF = 7 PRD = 10
Rv = 9v + xv and Rv = 7v + (10 - x)v
both R equal 9v + xv = 7v + 10v - 20x + xv
x = (7v + 10v - 9v)/20
x = 68/20
x = 3.4
OP = 3.4, O9 = 5 - 3.4 = 1.6
R = √9v−xv
= √9v−(3.4)v
= √92.56
9D = √(92.56v−(1.6)v
= √92.56v−2.56
= √90
CD = 2√90
Now Checking
OR = OQ + QR
= 1.6 + 5 = 6.6
OF = R = √92.56
RF = √92.56−43.56=√49=7
So, own Soln is correct:
The length of the chord that lies halfway between them is 2√90 units.