range of \({f(x) = 2x^2 - 8x + 1}\) if restricted to -1 ≤ x ≤ 2, or domain [-1,2]
\({f(-1)=2*(-1)^2 - 8 * (-1)+ 1 =11}\)
\({f(2)=2*(2)^2 - 8 * (2)+ 1 =-7}\)
so, range is:
{\({f(x)}\) element \({R}\):\( {-7 ≤f(x)≤11}\)}
interval:
[\({-7}\),\({11}\)]
