TheGingeriousAle ^{user is banned}

range of ${f(x) = 2x^2 - 8x + 1}$ if restricted to -1 ≤ x ≤ 2, or domain [-1,2]

${f(-1)=2*(-1)^2 - 8 * (-1)+ 1 =11}$

${f(2)=2*(2)^2 - 8 * (2)+ 1 =-7}$

so, range is:

{${f(x)}$ element ${R}$:${-7 ≤f(x)≤11}$}

interval:

[${-7}$,${11}$]