+0

# function

0
13
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+1347

The function \$f(x)\$ is defined only on domain \$[-1,2]\$, and is defined on this domain by the formula
\$\$f(x) = 2x^2-8x+1.\$\$
What is the range of \$f(x)\$? Express your answer as an interval or as a union of intervals.

Oct 13, 2023

#1
+2
+1

range of \({f(x) = 2x^2 - 8x + 1}\) if restricted to -1 ≤ x ≤ 2, or domain [-1,2]

\({f(-1)=2*(-1)^2 - 8 * (-1)+ 1 =11}\)

\({f(2)=2*(2)^2 - 8 * (2)+ 1 =-7}\)

so, range is:

{\({f(x)}\) element \({R}\):\( {-7 ≤f(x)≤11}\)}

interval:

[\({-7}\),\({11}\)]

Oct 14, 2023
#2
+2440
-5

For the record: "TheGingeriousAle" account is not under the control GingerAle.

.... I was wondering when you’d return... and what user name you’d create to impersonate GingerAle.  TheGingeriousAle is a likeable name. I’m rather amazed an obnoxious and noxious troll could create the name. ...Perhaps you didn’t. If you used an AI then it’s not really your creation.

You posted a correct math solution (without bullshit), which is also amazing...and you didn’t sign my initials. Is this a change in tactics or will the familiar “other shoe” drop in a future post?

...In any case, impersonating another member is a violation of the TOS. So this account, like all the others impersonating GingerAle, is subject to banning. ...And banned it will be, eventually...

GA

--. .-

GingerAle  Oct 14, 2023
edited by GingerAle  Oct 14, 2023