The function $f(x)$ is defined only on domain $[-1,2]$, and is defined on this domain by the formula

$$f(x) = 2x^2-8x+1.$$

What is the range of $f(x)$? Express your answer as an interval or as a union of intervals.

sandwich Oct 13, 2023

#1**+1 **

range of \({f(x) = 2x^2 - 8x + 1}\) if restricted to -1 ≤ x ≤ 2, or domain [-1,2]

\({f(-1)=2*(-1)^2 - 8 * (-1)+ 1 =11}\)

\({f(2)=2*(2)^2 - 8 * (2)+ 1 =-7}\)

so, range is:

{\({f(x)}\) element \({R}\):\( {-7 ≤f(x)≤11}\)}

interval:

[\({-7}\),\({11}\)]

TheGingeriousAle Oct 14, 2023

#2**-5 **

**For the record: "TheGingeriousAle" account is not under the control GingerAle.**

.... I was wondering when you’d return... and what user name you’d create to *impersonate* GingerAle. *TheGingeriousAle* is a likeable name. I’m rather amazed **an obnoxious and noxious troll** could create the name. ...Perhaps you didn’t. If you used an AI then it’s __not__ really your creation.

You posted a __correct__ math solution (without bullshit), which is also amazing...and you didn’t sign my initials. **Is this a change in tactics or will the familiar “ other shoe” drop in a future post?**

...In any case, **impersonating another member is a violation of the TOS**. So this account, like all the others impersonating GingerAle, is subject to banning. ...And banned it will be, eventually...

GA

--. .-

GingerAle
Oct 14, 2023