im not sure if you mean $${\frac{{\mathtt{27}}}{{\mathtt{3}}}}{\mathtt{\,-\,}}\left({\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{3}}}{{\mathtt{4}}}}\right)$$ or$${\frac{{\mathtt{27}}}{\left({\mathtt{3}}{\mathtt{\,-\,}}\left({\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{3}}}{{\mathtt{4}}}}\right)\right)}}$$but im assuming its the first one. ill do both anyway
for the first one:
$${\frac{{\mathtt{27}}}{{\mathtt{3}}}}{\mathtt{\,-\,}}\left({\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{3}}}{{\mathtt{4}}}}\right)$$
order of operations, 4 + 3/4 = 19/4
27/3 - 19/4 = 108/12 - 57/12
$${\mathtt{108}}{\mathtt{\,-\,}}{\mathtt{57}} = {\mathtt{51}}$$
$${\frac{{\mathtt{51}}}{{\mathtt{12}}}} = {\frac{{\mathtt{17}}}{{\mathtt{4}}}} = {\mathtt{4.25}}$$
for the other one
$${\frac{{\mathtt{27}}}{\left({\mathtt{3}}{\mathtt{\,-\,}}\left({\mathtt{4}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{3}}}{{\mathtt{4}}}}\right)\right)}}$$
first figure out the denominator deal of course
4+(3/4) =19/4
$${\frac{{\mathtt{19}}}{{\mathtt{4}}}} = {\mathtt{4.75}}$$
3-4.75=-1.75
$${\frac{{\mathtt{27}}}{-{\mathtt{1.75}}}} = {\mathtt{\,-\,}}{\frac{{\mathtt{108}}}{{\mathtt{7}}}} = -{\mathtt{15.428\: \!571\: \!428\: \!571\: \!428\: \!6}}$$
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