+0

infinite division function dealie?

0
376
1
+271

is there any way to make thispattern repeat infinitely but without me typing it forever? like is there a function for this

TheJonyMyster  Jun 23, 2015

#1
+26642
+10

I don't know of a universally accepted, concise representation for this, but I guess you could use something like the list form used for continued fractions. If we call the whole thing g(f(x)) then here this might look like:

g(f(x)) = [f(x); f(x+1), f(x+2), ... , f(x+n)]

Notice that the first term is followed by a semicolon, the others by a comma.

Or you could use

$$g(f(x))=f(x)+\frac{f(x)}{f(x+1)+}\frac{f(x+1)}{f(x+2)+}...\frac{f(x+n-1)}{f(x+n)}$$

a notation also used for continued fractions.

If you want an infinite repeat, you could just end each of the above with ... instead of adding the terms with n.

Have a look at https://en.wikipedia.org/wiki/Continued_fraction for other possibilities.

.

Alan  Jun 23, 2015
Sort:

#1
+26642
+10

I don't know of a universally accepted, concise representation for this, but I guess you could use something like the list form used for continued fractions. If we call the whole thing g(f(x)) then here this might look like:

g(f(x)) = [f(x); f(x+1), f(x+2), ... , f(x+n)]

Notice that the first term is followed by a semicolon, the others by a comma.

Or you could use

$$g(f(x))=f(x)+\frac{f(x)}{f(x+1)+}\frac{f(x+1)}{f(x+2)+}...\frac{f(x+n-1)}{f(x+n)}$$

a notation also used for continued fractions.

If you want an infinite repeat, you could just end each of the above with ... instead of adding the terms with n.

Have a look at https://en.wikipedia.org/wiki/Continued_fraction for other possibilities.

.

Alan  Jun 23, 2015

10 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details