+272 is there any way to make this
pattern repeat infinitely but without me typing it forever? like is there a function for this
+33661 I don't know of a universally accepted, concise representation for this, but I guess you could use something like the list form used for continued fractions. If we call the whole thing g(f(x)) then here this might look like:
g(f(x)) = [f(x); f(x+1), f(x+2), ... , f(x+n)]
Notice that the first term is followed by a semicolon, the others by a comma.
Or you could use
$$g(f(x))=f(x)+\frac{f(x)}{f(x+1)+}\frac{f(x+1)}{f(x+2)+}...\frac{f(x+n-1)}{f(x+n)}$$
a notation also used for continued fractions.
If you want an infinite repeat, you could just end each of the above with ... instead of adding the terms with n.
Have a look at https://en.wikipedia.org/wiki/Continued_fraction for other possibilities.
.
+33661 I don't know of a universally accepted, concise representation for this, but I guess you could use something like the list form used for continued fractions. If we call the whole thing g(f(x)) then here this might look like:
g(f(x)) = [f(x); f(x+1), f(x+2), ... , f(x+n)]
Notice that the first term is followed by a semicolon, the others by a comma.
Or you could use
$$g(f(x))=f(x)+\frac{f(x)}{f(x+1)+}\frac{f(x+1)}{f(x+2)+}...\frac{f(x+n-1)}{f(x+n)}$$
a notation also used for continued fractions.
If you want an infinite repeat, you could just end each of the above with ... instead of adding the terms with n.
Have a look at https://en.wikipedia.org/wiki/Continued_fraction for other possibilities.
.
