So guest
A radius of the biggest circle is OB OB=OC+CB = 32+36 = 68 unitis
AO also equals 68 units.
AC= AO+OC = 68+32=100
So the radius of the middle sized circle is 50 units
KS=50
-the area of trapezuim KSEM-
= average of the paralell sides * perpendicular height.
= 0.5( ME + KS) * ES
= 0.5( 18+ 50 ) * ES
= 34 * ES
SY=ME=18
KS = 50 = KY+YS = KY+18
so KY = 50-18=32 units.
Now KYM is a right angled triangle, t
The hypotenuse is KM = 50+18=68 units
one short side is KY = 32 units
KSEM = 34*ES = 34*60 = 2040 units squared. Im pretty sure
But I might have to double check my work but I think I got that right (I asked one of my class mates for help they said I was right)
If you need a more in debt answer just ask
-wolfie