Find the distance between the x-intercept and the y-intercept of the graph of the equation 5x - 12y = 40 .

Guest Jan 1, 2021

#1**0 **

Okay so lets start with

x intercept witch is (12, 0)

To find the y intercept, y x = 0 and that

12y = 60

y = 5 ( I think)

y intercept is ( 0, 5)

The distance Would be-

[ ( 12 - 0 )^2 + ( 5 - 0)^2 ] =

[ 12^2 + 5^2] =

[ 144 + 25 ] =

[ 169 ] =

13 units (If you need an more in debt answer feel free to ask)

-wolfie!

wolfiechan Jan 1, 2021

#2**0 **

Wait I might've done that wrong Im not sure (sorry ive been answering so many people so my brain is gone right now)

wolfiechan
Jan 1, 2021

#3**0 **

Hi Guest!

The x-intercept is 8, and the y-intercept is -10/3.

I think Wolfie accidentally by 60 instead of 40 when finding them.

**x-intercept**

x-intercept is when y = 0.

5x - 12(0) = 40

5x = 40

x = 8

**y-intercept**

The y-intercept is when x = 0.

5(0) - 12x = 40

-12x = 40

x = -40/12

x = -10/3

**Distance**

We can simply use a^2 + b^2 = c^2 since the x and y intercept form a right angle triangle.

(-10/3)^2 + 8^2 = 676/9

sqrt(676/9) = 26/3.

**Answer**

26/3

I hope this helped. :)))))

=^._.^=

catmg Jan 1, 2021