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# help with coordinates

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Find the distance between the x-intercept and the y-intercept of the graph of the equation 5x - 12y = 40 .

Jan 1, 2021

#1
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x intercept  witch is  (12, 0)

To  find the  y intercept, y  x  = 0 and that

12y  = 60

y = 5  ( I think)

y intercept is  ( 0, 5)

The distance Would be-

[ ( 12 - 0 )^2  + ( 5 - 0)^2 ]  =

[ 12^2 + 5^2]  =

[ 144 + 25 ]  =

[ 169  ]  =

13 units (If you need an more in debt answer feel free to ask)

-wolfie!

Jan 1, 2021
#2
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Wait I might've done that wrong Im not sure (sorry ive been answering so many people so my brain is gone right now)

wolfiechan  Jan 1, 2021
edited by wolfiechan  Jan 1, 2021
#4
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Hi Wolfie,

I think you may have messed up some of the numbers.

Woah, you stayed up quite late.

=^._.^=

catmg  Jan 1, 2021
#5
+315
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yeah sorry

wolfiechan  Jan 1, 2021
#3
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Hi Guest!

The x-intercept is 8, and the y-intercept is -10/3.

I think Wolfie accidentally by 60 instead of 40 when finding them.

x-intercept

x-intercept is when y = 0.

5x - 12(0) = 40

5x = 40

x = 8

y-intercept

The y-intercept is when x = 0.

5(0) - 12x = 40

-12x = 40

x = -40/12

x = -10/3

Distance

We can simply use a^2 + b^2 = c^2 since the x and y intercept form a right angle triangle.

(-10/3)^2 + 8^2 = 676/9

sqrt(676/9) = 26/3.