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Find the distance between the x-intercept and the y-intercept of the graph of the equation 5x - 12y = 40 .

 Jan 1, 2021
 #1
avatar+315 
0

Okay so lets start with

x intercept  witch is  (12, 0)

 

To  find the  y intercept, y  x  = 0 and that

 

12y  = 60

y = 5  ( I think)

 

  y intercept is  ( 0, 5)

 

The distance Would be-

  [ ( 12 - 0 )^2  + ( 5 - 0)^2 ]  =

 [ 12^2 + 5^2]  =

[ 144 + 25 ]  =

[ 169  ]  =  

 

13 units (If you need an more in debt answer feel free to ask)

-wolfie!

 Jan 1, 2021
 #2
avatar+315 
0

Wait I might've done that wrong Im not sure (sorry ive been answering so many people so my brain is gone right now)

wolfiechan  Jan 1, 2021
edited by wolfiechan  Jan 1, 2021
 #4
avatar+814 
0

Hi Wolfie,

 

I think you may have messed up some of the numbers. 

Woah, you stayed up quite late. 

 

=^._.^=

catmg  Jan 1, 2021
 #5
avatar+315 
+1

yeah sorry 

wolfiechan  Jan 1, 2021
 #3
avatar+814 
0

Hi Guest!

 

The x-intercept is 8, and the y-intercept is -10/3. 

I think Wolfie accidentally by 60 instead of 40 when finding them. 

 

x-intercept

x-intercept is when y = 0. 

5x - 12(0) = 40

5x = 40

x = 8

 

y-intercept

The y-intercept is when x = 0. 

5(0) - 12x = 40

-12x = 40

x = -40/12

x = -10/3

 

Distance

We can simply use a^2 + b^2 = c^2 since the x and y intercept form a right angle triangle. 

(-10/3)^2 + 8^2 = 676/9

sqrt(676/9) = 26/3. 

 

Answer

26/3

 

I hope this helped.  :)))))

=^._.^=

 Jan 1, 2021

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