xerxes

see here:

$${\mathtt{V}} = {\mathtt{b}}{\mathtt{\,\times\,}}{\mathtt{h}}$$

b is the base area

h is the height

b is the area of the rectangle

$${\mathtt{b}} = {\mathtt{a}}{\mathtt{\,\times\,}}{\mathtt{b}}$$

Please mark this post as "answer" if it solved your problem or question

$${{\mathtt{4}}}^{{\mathtt{3}}} = {{\mathtt{2}}}^{{\mathtt{n}}} \Rightarrow {\mathtt{n}} = {\frac{{ln}{\left({\mathtt{64}}\right)}}{{ln}{\left({\mathtt{2}}\right)}}} \Rightarrow {\mathtt{n}} = {\mathtt{6}}$$

Please mark this post as answer if it solved your problem, thanks

Well, you can just state the first 7 digits of this 48 digit number.

The number will look like this:

$${\mathtt{777\,777\,700\,000\,000\,000\,000\,000\,000\,000\,000\,000\,000\,000\,000\,000}}$$

or

$${\mathtt{777\,777\,777\,777\,777\,777\,777\,777\,777\,777\,777\,777\,777\,777\,777\,777}}$$

Cheers

Das ist gleichbedeutend mit:

$${f}{\left({\mathtt{x}}\right)} = {\mathtt{k}}{\mathtt{\,\times\,}}{\mathtt{x}}$$

Dies wiederum ist eine ganz normale Funktion. Das mit dem Pfeil ist nur eine etwas andere Schreibweise.

$${\mathtt{a}} = {\frac{{\mathtt{1}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}\left({\mathtt{b}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}\right){\mathtt{\,\times\,}}{\mathtt{5}}$$                  Rearange (to show what we are doing)

$${\mathtt{a}} = {\frac{{\mathtt{1}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}{\mathtt{5}}{\mathtt{\,\times\,}}\left({\mathtt{b}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}\right)$$                   Simplify

$${\mathtt{a}} = {\frac{{\mathtt{5}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}\left({\mathtt{b}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}\right)$$                          Expand the brackets

$${\mathtt{a}} = {\frac{{\mathtt{5}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{5}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}{\mathtt{5}}$$                            Simplify

$${\mathtt{a}} = {\frac{{\mathtt{5}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}{\mathtt{b}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{25}}}{{\mathtt{2}}}}$$

The exact value of a depends on b.

Please note: Thanks CPhil for noticing, I have a "typo" in my answer. Please refer to his correct solution.

1.

$${\mathtt{76.5}}{\mathtt{\,-\,}}{\mathtt{10}} = {\frac{{\mathtt{133}}}{{\mathtt{2}}}} = {\mathtt{66.5}}$$

$${\frac{{\mathtt{66.5}}}{{\mathtt{2}}}} = {\frac{{\mathtt{133}}}{{\mathtt{4}}}} = {\mathtt{33.25}}$$

The shoes are $33.25 each pair.

2.

$${\mathtt{300}}{\mathtt{\,-\,}}{\mathtt{50}} = {\mathtt{250}}$$

$${\frac{{\mathtt{250}}}{{\mathtt{5}}}} = {\mathtt{50}}$$

You need 50 weeks of saving.

3.

$${\mathtt{108}}{\mathtt{\,-\,}}{\mathtt{6}} = {\mathtt{102}}$$

$${\frac{{\mathtt{102}}}{{\mathtt{3}}}} = {\mathtt{34}}$$

The player bats in 34 times.

4.

$${\mathtt{35}}{\mathtt{\,-\,}}{\mathtt{8}} = {\mathtt{27}}$$

$${\frac{{\mathtt{27}}}{{\mathtt{5}}}} = {\mathtt{5.4}}$$

She can take 5 children with her (and keeps $2).

5.

$${\mathtt{5\,610}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1\,618}} = {\mathtt{7\,228}}$$

$${\frac{{\mathtt{7\,228}}}{{\mathtt{2}}}} = {\mathtt{3\,614}}$$

The depth of Kazumura Cave is 3614 feet.

I hope I could help you, even tough this is not the best way to learn it ;)

$$\\ \left{$-5w+11=51$ \hspace{36mm} | $-11$} \\ \left{$-5w = 40$ \hspace{42mm} | $:5$} \\ \left{$-w = 8$ \hspace{48mm} | $*(-1)$} \\ \left{$w = -8$} \\$$

$${\frac{{\mathtt{a}}}{{\mathtt{c}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{b}}}{{\mathtt{d}}}}$$

insert the values for a, b, c and d

$${\mathtt{\,-\,}}{\frac{{\mathtt{7}}}{{\mathtt{82}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{8}}}{{\mathtt{20}}}} = {\mathtt{\,-\,}}{\frac{{\mathtt{199}}}{{\mathtt{410}}}} = -{\mathtt{0.485\: \!365\: \!853\: \!658\: \!536\: \!6}}$$

$${\frac{{\mathtt{1}}}{{\mathtt{3}}}}{\mathtt{\,\times\,}}{\mathtt{15}}{\mathtt{\,\times\,}}{\mathtt{4}} = {\mathtt{20}}$$

or

$${\frac{\left({\mathtt{1}}{\mathtt{\,\times\,}}{\mathtt{15}}{\mathtt{\,\times\,}}{\mathtt{4}}\right)}{{\mathtt{3}}}} = {\mathtt{20}}$$