2^3*4^3=2^3*2^n=2^9 What is n

$${{\mathtt{4}}}^{{\mathtt{3}}} = {{\mathtt{2}}}^{{\mathtt{n}}} \Rightarrow {\mathtt{n}} = {\frac{{ln}{\left({\mathtt{64}}\right)}}{{ln}{\left({\mathtt{2}}\right)}}} \Rightarrow {\mathtt{n}} = {\mathtt{6}}$$

Please mark this post as answer if it solved your problem, thanks