XxmathguyxX

prime factorization:

25=5x5

complete!

no it is not prime

25= 5x5 @ guest it can be divided by 5

ok, so

6x - x^2 = k

everytime x is increased by 1, 6x is increased by 6

everytime x is increased by 1, x^2 is increased by 2x+1, since,

\((x+1)\times(x+1)\)

\(=x(x+1)+1(x+1)\)

\(=x^2+x+x+1\)

so we added 2x+1

I'll let you figure this out 

p.s also trial and error will work just as fine

would you mind explaining what R4 and R3 is?

Since, \(\overline{DC}\) is parellel to \(\overline{AB}\), \(\angle{DCA}\) is the same as \(\angle{CAB}\).

\(\angle{ACB}=180-(40+73)\)

\(=180-113=67\)

so 67 is your answer!

\(2x^2=4x+9\)

\(2x^2-9=4x\)

\(2x^2-4x-9=0\)

\(x_{1,\:2}=\frac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:2\left(-9\right)}}{2\cdot \:2}\)

\(x_{1,\:2}=\frac{-\left(-4\right)\pm \:2\sqrt{22}}{2\cdot \:2}\)

\(x_1=\frac{-\left(-4\right)+2\sqrt{22}}{2\cdot \:2},\:x_2=\frac{-\left(-4\right)-2\sqrt{22}}{2\cdot \:2}\)

\(x=\frac{2+\sqrt{22}}{2},\:x=\frac{2-\sqrt{22}}{2}\)

In this case, it is

\(x=\frac{2+\sqrt{22}}{2}\)

2+22+2=26

so 26 is your answer!

finally i can breath....

i've been holding my breath for 10 minutes now

THANK YOU CPHILL for adding proof to my solution. Also thanks to @Builderboi for providing an answer. Thanks ya'll!

let's see what cphill gets.....

*getting so nervous*

*on the brink of extiction*

*super fast breathing*