+0  
 
0
60
1
avatar

In the figure, $\overline{DC}$ is parallel to $\overline{AB}$. We have $\angle DCA = 40^\circ$ and $\angle ABC = 73^\circ$. Find $\angle ACB$.

 Feb 27, 2022
 #1
avatar+360 
+3

Since, \(\overline{DC}\) is parellel to \(\overline{AB}\)\(\angle{DCA}\) is the same as \(\angle{CAB}\).

\(\angle{ACB}=180-(40+73)\)

\(=180-113=67\)

so 67 is your answer!

 Feb 27, 2022
edited by XxmathguyxX  Feb 27, 2022

23 Online Users

avatar