In the figure, $\overline{DC}$ is parallel to $\overline{AB}$. We have $\angle DCA = 40^\circ$ and $\angle ABC = 73^\circ$. Find $\angle ACB$.
+364 Since, \(\overline{DC}\) is parellel to \(\overline{AB}\), \(\angle{DCA}\) is the same as \(\angle{CAB}\).
\(\angle{ACB}=180-(40+73)\)
\(=180-113=67\)
so 67 is your answer!
