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# heeeeelpp

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In the figure, $\overline{DC}$ is parallel to $\overline{AB}$. We have $\angle DCA = 40^\circ$ and $\angle ABC = 73^\circ$. Find $\angle ACB$.

Feb 27, 2022

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Since, $$\overline{DC}$$ is parellel to $$\overline{AB}$$$$\angle{DCA}$$ is the same as $$\angle{CAB}$$.

$$\angle{ACB}=180-(40+73)$$

$$=180-113=67$$