zacismyname

$$2\sqrt{75}\times\sqrt{72}$$

$$2\sqrt{75\times72}$$

$$2\sqrt{5400}$$

$$2\sqrt{100}\times\sqrt{54}$$

$$2\times{10}\times\sqrt{9}\times\sqrt{6}$$

$$2\times{10}\times{3}\times\sqrt{6}$$

$$60\sqrt6$$

Area of a square = length^2

$$x^2=361$$

$$\sqrt{x^2}=\sqrt{361$$

$$x=19 ft$$ 

Nah its $$\sqrt{16}$$ ;)

$${\frac{{\mathtt{1}}}{{{\mathtt{2}}}^{-{\mathtt{3}}}}}$$

$${\frac{\left({\frac{{\mathtt{1}}}{{\mathtt{1}}}}\right)}{\left({\frac{{\mathtt{1}}}{{{\mathtt{2}}}^{{\mathtt{3}}}}}\right)}}$$

$$\left({\frac{{\mathtt{1}}}{{\mathtt{1}}}}\right){\mathtt{\,\times\,}}\left({\frac{{{\mathtt{2}}}^{{\mathtt{3}}}}{{\mathtt{1}}}}\right)$$

$${{\mathtt{2}}}^{{\mathtt{3}}}$$

If you get used to doing this you can skip straight from $${\frac{{\mathtt{1}}}{{{\mathtt{2}}}^{-{\mathtt{3}}}}}$$ to $${{\mathtt{2}}}^{{\mathtt{3}}}$$

$${\mathtt{1.1}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{4}}} = {\mathtt{0.000\: \!11}}$$

(fyi $${{\mathtt{10}}}^{-{\mathtt{4}}} = {\frac{{\mathtt{1}}}{{{\mathtt{10}}}^{{\mathtt{4}}}}} = {\frac{{\mathtt{1}}}{{\mathtt{10\,000}}}}$$)

9*12=108

Next time you could use a calculator :)

No you got the same answer :)

The volume of the cone is 294.38 . The radius of the base is 7.5 cm . Which of the following could be the height of the cone ? 

$${\mathtt{V}} = {\frac{{\mathtt{\pi}}{\mathtt{\,\times\,}}{{\mathtt{r}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{h}}}{{\mathtt{3}}}}$$

$${\mathtt{294.38}} = {\frac{{\mathtt{\pi}}{\mathtt{\,\times\,}}{{\mathtt{7.5}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{h}}}{{\mathtt{3}}}}$$                    Times both sides by 3

$${\mathtt{883.14}} = {\mathtt{\pi}}{\mathtt{\,\times\,}}{\mathtt{56.25}}{\mathtt{\,\times\,}}{\mathtt{h}}$$           Divide both sides by 7.5^2 which = 56.25 and pi

$${\mathtt{5}} = {\mathtt{h}}$$ (nearest whole. the actual figure is around 4.998)

The answer is b, 5cm.

$$\frac{125}{200}=\frac{5}{8}=0.625$$

(divide the numerator and denominator by their highest common factor = 25)