The volume of the cone is 294.38 . The radius of the base is 7.5 cm . Which of the following could be the height of the cone ?
a.4cm
b.5cm
c.6cm
d.7cm
The volume of the cone is 294.38 . The radius of the base is 7.5 cm . Which of the following could be the height of the cone ?
$${\mathtt{V}} = {\frac{{\mathtt{\pi}}{\mathtt{\,\times\,}}{{\mathtt{r}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{h}}}{{\mathtt{3}}}}$$
$${\mathtt{294.38}} = {\frac{{\mathtt{\pi}}{\mathtt{\,\times\,}}{{\mathtt{7.5}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{h}}}{{\mathtt{3}}}}$$ Times both sides by 3
$${\mathtt{883.14}} = {\mathtt{\pi}}{\mathtt{\,\times\,}}{\mathtt{56.25}}{\mathtt{\,\times\,}}{\mathtt{h}}$$ Divide both sides by 7.5^2 which = 56.25 and pi
$${\mathtt{5}} = {\mathtt{h}}$$ (nearest whole. the actual figure is around 4.998)
The answer is b, 5cm.
The formula for the volume of a cone is V=1/3BH or V=$${\mathtt{\pi}}$$r^2H, in which B equals the area of the base,H is the height of the cone, and r is the radius of the base.
Plugging in the values, we get 294.38=1/3*$${\mathtt{\pi}}$$*56.25*H
To solve for H, isolate the variable by dividing both sides by $${\mathtt{\pi}}$$, 1/3, and 56.25
294.38/(1/3)/$${\mathtt{\pi}}$$/56.25 is approximately 5.
The correct answer would be B, 5cm.
The volume of the cone is 294.38 . The radius of the base is 7.5 cm . Which of the following could be the height of the cone ?
$${\mathtt{V}} = {\frac{{\mathtt{\pi}}{\mathtt{\,\times\,}}{{\mathtt{r}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{h}}}{{\mathtt{3}}}}$$
$${\mathtt{294.38}} = {\frac{{\mathtt{\pi}}{\mathtt{\,\times\,}}{{\mathtt{7.5}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{\mathtt{h}}}{{\mathtt{3}}}}$$ Times both sides by 3
$${\mathtt{883.14}} = {\mathtt{\pi}}{\mathtt{\,\times\,}}{\mathtt{56.25}}{\mathtt{\,\times\,}}{\mathtt{h}}$$ Divide both sides by 7.5^2 which = 56.25 and pi
$${\mathtt{5}} = {\mathtt{h}}$$ (nearest whole. the actual figure is around 4.998)
The answer is b, 5cm.
$${\mathtt{1.1}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{4}}} = {\mathtt{0.000\: \!11}}$$
(fyi $${{\mathtt{10}}}^{-{\mathtt{4}}} = {\frac{{\mathtt{1}}}{{{\mathtt{10}}}^{{\mathtt{4}}}}} = {\frac{{\mathtt{1}}}{{\mathtt{10\,000}}}}$$)
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