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Is it this :

360 - 187 = 173

173 - 141 = 32

(141 - 320 / 2 

109 / 2

X = 54.5

Check the answer given at : https://web2.0calc.com/questions/math-problem_67#r1 where you first asked it.  Don't repeat a question without checking the original!

NB Geno made a slight mistake by inverting the ratio on the RHS. 

6 / (1/4)= 6 * 4= 24.

Make sure you're learning from this and not just looking for the answers!!

So it would be (187 - 141) / 2  = 23

angle x = 23 degrees?

1)  Total up the frequency.

     a) To find the probability, divide the number of times that a 3 was rolled (11) by the total.

     b) To find the probability, divide the number of times that a 6 was rolled (12) by the total.

          Then, multiply that probability by (500 + the total).

Angle(x) is found by taking one-half of the difference between the larger intercepted arc and the smaller intercepted arc.

The larger intercepted arc is 141^o.

Find the size of the smaller intercepted arc and use the formula.

thanks. I am getting confused on the second one because in the problem you did, you subtracted the 1-9. In the second problem I tried doing that same thing. It was incorrect. 9-(1-x)^2= (8-x)^2 =x^2+16x+64 that was incorrect. I guess Im wondering where I went wrong?

we are trying to find h(x) though. In your answer you gave h(x) We don't know that. The final answer you gave was the problem we started with sqrt of x^9+9

edit- Okay I see now how you got hx I was confused at first. Thanks.

Masses are related by their volumes.

If two solids are similar their volumes are related to their corresponding lengths by their cubes in this way:

   If a length of solid A has length "L_a" and the corresponding length of solid B has length "L_b"

   and if the volume of solid A has volume "V_a" and the volume of solid B has volume "V_b",

   then:  V_a / V_b  =  (L_a)³ / (L_b)³.

Also, for areas (by their squares):  A_a / A_b  =  (L_a)² / (L_b)²

Let's use this area relationship to find the lengths and then use these lengths to find the volumes.

A_a / A_b  =  (L_a)² / (L_b)²     --->   40.32 / 28  =  (L_a)² / (L_b)²​     --->   sqrt(40.32) / sqrt(28)  =  L_a / L_b

Now, let's use the volume formula     --->     V_a / V_b  =  (L_a)³ / (L_b)³     --->    V_a / V_b  =  [ sqrt(40.32) ]³ / [ sqrt(28) ]³

V_a  =  [ sqrt(40.32) ]³   =  256.024         V_b  =  [ sqrt(28) ]³  =  148.162

We can now use these values for the volumes to find the mass of A:

 mass(A) / mass(B)  =  V_a / V_b     --->     mass(A) / 6912  =  256.024  / 148.162 

--->     mass(A)  =  11944 grams

Thank you!

Thank you!

Find the measure of arc AB in degrees.

This question was already posted by you and answered.

Edit: If you still don't understand, ask on your previous quesiton thread instead of reposting.

Ok.. Just checking... The supplememt of angle A is 180 - 133= 47 degrees. The measure of Arc AB is 2 * 47 degrees= 94 degrees.

2)  Since the pentagon is regular each of its interior angles is  =  (5 - 2)·180^o / 5  =  108^o  =  a

      To find angle(b):  it is a base angle of an isosceles triangle

               To find the third angle:  360^o - 108^o - 60^o - 60^o  =  132^o

                So, b  =  (180^o - 132^o) / 2  =  24^o 

Minor arc AB because the Major arc would be AEB

Can you clarify if the question means Major or Minor arc AB?

Areas scale as length squared, whereas volumes scale as length cubed.  So the volume ratio varies as the cube of the square root of area ratio.

i.e.  \(\frac{V_A}{V_B}= (\frac{A_A}{A_B })^{3/2}\)

Mass scales with volume, so \(\frac{M_A}{6912}=(\frac{28}{40.32})^{3/2}\) 

I'll leave you to crunch the numbers.

Thanks Melody, this answer als provides me a different insight the problem. 

Assuming RS is a diagonal, then draw a line from the centre to T and you have an isosceles triangle.  The angle S (call it x) is the same as the angle between the line from the centre to T and that from T to S, so you have 2x + 48 = 180, from which you can find x.

What cone?!!!