All Answers 355975 Answers

I'm so sorry! I didn't know it was asked already. Thanks for pointing that out. Have a good day!

Thank You very much

The max area will  be a square  with a side  of  40/4   = 10 ft

So....the max area  =(10ft)^2  =  100 ft^2

Quadrant II

(-2 + 4i) * i^3  =    -2i^3  + 4i^4   =  -2 (-i) + 4  =   4 + 2i

So....multiplying by i^3  results in a 90° clockwise rotation

So the resulting product lies in Quadrant 1

1 , 7 , 11 , 13 , 17 , 19 , 23 , 29 , 31 , 37 , 41 , 43 , 47 , 53 , 55 , 59 , 61 , 65 , 67 , 71 , 73 , 79 , 83  >>Euler'sPhi = 23

What figure  ?????

C  = 3.14 * diameter

50 =  3.14 * diameter         divide both sides by   3.14

15.92 m =  diameter

50 / 8   =   25 / 4   =   6 + 1/4  times

See my answer here :

https://web2.0calc.com/questions/geometry_39190

Please try and understand instead of a direct answer!

:D

I see....since the workers are paid for 9.3 pounds for each hr  or part of an hour they work.....we need to round 8.75  up to 9

So we have

2 * 9.3 * 9  =   167.4 pounds

I agree

The "new" pyramid and the original pyramid are similar figures

The  scale  factor  of  the  "new"  pyramid  to the original pyramid  =  1/4

Let the  volume of the original pyramid  be  = V

The  volume  of the "new" pyramid  =  V *  (1/4)^3  =  V / 64

The volume  of the remaining frustum  =   V - V/64  = (63/64)V

So  the volume of the frustum  is  (63/64)  of volume of the original pyramid

1 - sumfor(n, 1, 99, 1 / (n*(n+1)) = 99 / 100

2 - sumfor(n, 1, 98, 1 / (n^3 +3*n^2+ 2*n))= 4949 / 19800

modulus  = sqrt  [ 6^2  + (-4)^2 ] =   sqrt [ 36  + 16 ] =  sqrt (52)  =  2sqrt (13)

We are supposed to help you understand how to do the problem so you can answer them yourself

x is 1/3 of y

the answer is wrong

Wow... ANOTHER AOPS QUESTION

Thank you very much!