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That's what I put down but it was WRONG!!

Are there any other ideas?

If a number were less than -3, the only possible choice is -5. There are no options here greater than 5 though, so it is not possible.

Although I believe the problem should be phrased "Which number is less than -3 and greater than 5."

We have a ratio of dollars over lire- 1.5:1200.

In order to get to 1000000 lire, we must multiply the entire ratio by 1000000/1200=833 1/3. So we have:

1.5:1200

=1.5*833 1/3 : 1200 * 833 1/3

= 1250:1000000.

So $1250 is equivalent to 1000000 lire.

4x+6x=30

10x=30

x=3.

4x + 6x = 30

Add the like terms (4x + 6x)

10x = 30 

Divide 10 by 10x and 30 to get the ten to the other side so x is on its own.

x = 3

(-4)^3 + (-5) - (-6)^3 -15 

=-64-5-(-216)-15

=-69+216-15

=-69+201

=132

The largest possible values of b is (3)*(1) = 3.

DE:DC = 2/5.

5 inch line

  one is   'x'    and the other is   x - 2.5     ( 2 1/2 inches shorter than 'x') 

         added together they have to equal 5 inches

              x     +      x-2.5     = 5       now solve for 'x'    and the other segment is x-2.5 inches

Complementary means they sum up to 90 degrees

4x-7      +    x+12       = 90      First, solve for x      then angle1 = 4x-7      angle 2 = x+12

The smallest repunit =111,111

111,111 / 21 =5,291

We first turn 3x+4y=12 into standard form:

4y=-3x+12

y=-3/4x+3

By knowing the 2nd line is parrelell to the first, the slopes are the same:

y=-3/4x+b

Plugging in (5,4) into the equation:

4=-15/4+b

b=1/4

Final equation=y=-3/4+1/4.

Don't keep repeating the same question several times within a short period of time!

Expand the left hand side

\(abx^2+(a^2+b^2)x+ab=26x^2+[]x + 26\)

So we must have 

a*b = 26

a and b are integers, so the possibilities are 

a = 1   b = 26

a = 2   b = 13    

(or the same with a and b switched).

Hence [] must be either \(1^2+26^2\)   or  \(2^2+13^2\)

I'll leave you to decide which is smaler.

I need to find x and y.

We'll miss you ilorty!!!  Best of luck with your school/homework!

For all the rectangular sides, we have \(4\cdot (8 +10 + 6) = 96\), and for the top and bottom, we have \(2 \cdot 24 = 48\), and finally \(96 + 48 = \boxed{144}\)

A. \(- \dfrac{4}{5}\)

B. Undefined

b. The probability is 3/5.

c. The probability is 7/20.

We have 2 cases, \(5 + 3w \le 2, and -5 - 3w \le 2\)

Starting with the first case \(​​5 + 3w \le 2\) , we can subtract 5 from both sides to get \(3w \le -3\), and then divide by 3 for an answer of \(w \le -1\), keeping in mind 3 is positive so we don't switch the sign.

Now for our second case, \(- 5 - 3w \le 2\), we add five to both sides giving us, \(- 3w \le 7\), now dividing by \(-3\) and making sure we flip the sign, we get, 

\(w \ge - \dfrac{7}{3}\)

But wait, we still have to combine our answers giving us \(\boxed{-\frac{7}{3} \le w \le -1}\)

{A, A, D, R} | {A, A, D, S} | {A, A, D, T} | {A, A, D, U} | {A, A, D, Y} | {A, A, R, S} | {A, A, R, T} | {A, A, R, U} | {A, A, R, Y} | {A, A, S, T} | {A, A, S, U} | {A, A, S, Y} | {A, A, T, U} | {A, A, T, Y} | {A, A, U, Y} | {A, D, R, S} | {A, D, R, T} | {A, D, R, U} | {A, D, R, Y} | {A, D, S, T} | {A, D, S, U} | {A, D, S, Y} | {A, D, T, U} | {A, D, T, Y} | {A, D, U, Y} | {A, R, S, T} | {A, R, S, U} | {A, R, S, Y} | {A, R, T, U} | {A, R, T, Y} | {A, R, U, Y} | {A, S, T, U} | {A, S, T, Y} | {A, S, U, Y} | {A, T, U, Y} | {D, R, S, T} | {D, R, S, U} | {D, R, S, Y} | {D, R, T, U} | {D, R, T, Y} | {D, R, U, Y} | {D, S, T, U} | {D, S, T, Y} | {D, S, U, Y} | {D, T, U, Y} | {R, S, T, U} | {R, S, T, Y} | {R, S, U, Y} | {R, T, U, Y} | {S, T, U, Y} = 50 Combinations.

S A T U R D A Y = 8 Letters. It is much easier to list the combinations first and then convert them to permutations. There are: [15 x 4!/2] + [35 x 4!] =180 + 840 =1,020 four-letter permutations or "words".

Thank you!

Hint: *2+3x-7-x can be rewritten as 3x-x-7+2*