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https://web2.0calc.com/questions/help-pls_81

Incorrect. The reccursion does not give you that result :P.

What is the sum of all values of z such that z^2 = 12z - 7 + 9z - 5?

Hello Guest!

\(z^2-21z+12=0\\ z=10.5\pm \sqrt{110.25-12}\\ z=10.5\pm \sqrt{98.25}\\ \sum z=20.412114+0.587886\)

\(\sum z=21\)

  !

By using the recursion, $a_8 = 128$.

[4 C 3] / 2^4 ==4 / 16 ==1/4 - probability of 3 heads or 3 tails.

Find C

Hello Guest!

\(p - 2q = 0\\ q - 2r = 0\\ p + r = 8 \)

\(p=2q=8-r\)

          \(q=2r\)

        \(\underline{2q=4r}\)

          \(0=8-5r\)

          \(r=\frac{8}{5}\)

\(q=2r=2\cdot \frac{8}{5}\)

\(q=3\frac{1}{5}\)

\(p+r=8\\ p=8-r=8-\frac{5}{8}\)

\(p=7\frac{3}{8}\)

\(The\ ordered\ triple\ (p,q,r)\ is\ \color{blue}(7\frac{3}{8},3\frac{1}{5},1\frac{3}{5})\)

  !

The correct answer is A, B, C.

Slope of x + 3y = -5: 1/3

Equation of line: y - 2 = 1/3(x + 7)

==> 3y - 6 = x + 7

==> x - 3y + 13 = 0

==> 3x/13 - 9y/13 + 3 = 0

==> B - A = -9/13 - 3/13 = -12/13

add condition A)  PQ = PR    

Then you have                      PQ  =  PR  

                                  angle QPS  =  angle RPS  

                                              PS  =  PS   

The triangles are congruent by Side-Angle-Side.  That's either an axiom or a theorem, I don't remember which.  

_.

Cross multiply to get $a-3=-a^2\implies a^2+a-3=0$. Solve this with the quadratic formula.

Let $x$ be the distance from the lower-left vertex to the intersection of the diagonals. Let $y$ be the same distance just for the lower right. Similar triangles gives

$$\frac{x}{35-x}=\frac{y}{120-y}=\frac{75}{50}\implies x=21, y=72$$

Heron's formula tells us that the area of the lower similar triangle (larger one) is $756$. Hence the height of the triangle is $\frac{504}{25}$. Then the height of the other one is $\frac{336}{25}$. So the whole height is $\frac{168}{5}$. The average of the bases is $\frac{125}{2}$. Thus the area of the trapezoid is $2100$.

Let $x$ be the distance from the lower-left vertex to the intersection of the diagonals. Let $y$ be the same distance just for the lower right. Similar triangles gives

$$\frac{x}{35-x}=\frac{y}{120-y}=\frac{75}{50}\implies x=21, y=72$$

Heron's formula tells us that the area of the lower similar triangle (larger one) is $756$. Hence the height of the triangle is $\frac{504}{25}$. Then the height of the other one is $\frac{336}{25}$. So the whole height is $\frac{168}{5}$. The average of the bases is $\frac{125}{2}$. Thus the area of the trapezoid is $2100$.

please answer this

416 numbers        2^8 + 2^5 + 2^7

The vertex is shifted eight units to the LEFT    to    -7,-2

Foley is behind by 12 - 8 = 4 km.

THANK YOU SO MUCH!

\(2a_1 - a_2a_0 = (-1)^1 \quad \rightarrow \quad 2(5) - a_2 \cdot 1 = -1 \quad \rightarrow \quad a_2 = 11\)

\(2a_2 - a_3a_1 = (-1)^2 \quad \rightarrow \quad 2(11) - a_3 \cdot 5 = 1 \quad \rightarrow \quad a_3 = \boxed{\frac{21}{5}}\)

To divide a fraction, multiply by the reciprocal.

\(\frac{1}{4} \div \frac{-3}{8} = \frac{1}{4} \cdot \frac{8}{-3} = \frac{8}{-12} = \boxed{-\frac{2}{3}}\)

To divide a fraction, multiply by its reciprocal.

\(\frac{-7}{10} \div \frac{2}{5} = \frac{-7}{10} \cdot \frac{5}{2} = \frac{-35}{20} = \boxed{\frac{-7}{4}}\)

\(3(x-4) - 2(x^2 - x + 7) + 5(x-1) + 3(x+8)\)

\((3x - 12) - (2x^2 - 2x - 14) + (5x - 5) + (3x + 24)\)

\(3x - 12 - 2x^2 + 2x + 14 + 5x - 5 + 3x + 24\)

\(-2x^2 + 13x + 21 \)

constant term = 21

P==Pears,  L==Lemons

[18 + P] / [42 - L] ==3 /4,
[36 - P] / [50 + L] ==1/2, solve for A, B
L==10,  P==6
Box F ==18 + 6=24 pears
           ==42 - 10=32 lemons

Box G ==36 - 6 ==30 pears
            ==50 + 10=60 lemons.

(a) - In the end, there were ==32 Lemons in Box F

(b) - In the end, there were: 30  -  24 ==6 more Pears in Box G than Box F

25 x   + 14   =  3 out of (3+1) x = 3/4 x     where x = number of questions

2/5 x + 14 = 3/4 x

nice