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Velocity is rate of change of distance, so, if x is distance, velocity,v is given by:

l.   2t + 5

ll.  1/2

lll.  t/2

lV. 2t + 3/4

Just plug in t = 5 (where approriate) to get the velocities.

The ratio of the circumference to the diameter of a circle.

b.  tan(elevation angle) = (height of flagpole above ground - height of student above ground)/distance from base

tan(22°) = (h - 18)/50   where h = height of flagpole above ground

Multiply both sides by 50

50*tan(22°) = h - 18

Add 18 to both sides 

h = 50*tan(22°) + 18  ≈ 38.2 ft

d. 

Natural numbers are the counting numbers 1, 2, 3, 4, ... etc.

tan(elevation angle) = height of pole/length of shadow

elevation angle = tan-1(4/6) ≈ 33.7°

What is (1 3/4 + 2 1/3)+4 2/3

\(\begin{array}{rcl} \left(1 \frac34 + 2 \frac13 \right)+4 \frac23 \\ &=& 1 \frac34 + 2 \frac13+4 \frac23 \\ &=& 1 + \frac34 + 2 + \frac13+4 + \frac23 \\ &=& 1 + 2 + 4 + \frac34 + \frac13 + \frac23 \qquad | \qquad \frac13 + \frac23 = \frac33 = 1 \\ &=& 1+2+4 + \frac34 + 1\\ &=& 1+2+4+1+ \frac34 \\ &=& 8 + \frac34 \\ &=& 8 \frac34 \\ &=& 8.75 \end{array} \)

what is 1/sinxcosx

\(\begin{array}{rcl} \frac{1}{ \sin{(x)}\cdot \cos{(x)}} & \qquad | \qquad \boxed{~ \sin{(2x)} = 2\cdot \sin{(x)}\cdot \cos{(x)} ~ }\\\\ = \frac{1} { \frac{ \sin{(2x)}} {2} } \\ \frac{1}{ \sin{(x)}\cdot \cos{(x)}}=\mathbf{ \frac{2} { \sin{(2x)} } } \\ \end{array}\)

Hallo

hallo

what is t if the equation is

-16(txt)+240=0 Does this mean: -16t^2 + 240=0? If so, then we have: -16t^2=-240, we divide both sides by -16=t^2=-240/-16=t^2=15

t^2=15

t=sqrt(15)=3.8730

Why don't you use the well-known formula for the energy of elementary particles: E=hc/y. Since you don't have "y", which is the wavelength of the photon, then just multiply Planck's constant by "c", which is the speed of light. That should give you the energy of the photon in "Ev", or electron volts. It's going to be a very small number because of Planck's constant. However, you may have to calculate the wavelength of the photon by using the formula: y=c/f, "f" being the frequency of the photon.

Why don't try these and let us know what you got. Good luck.

\(6x + 10 = x \\ 5x + 10 = 0 \\ 5x = -10 \\ x = -\dfrac {10}{5} = -2\)

\(-16 t^2 + 240 = 0\\ 16t^2 = 240 \\ t^2 = 15 \\ t = \pm \sqrt{15}\)

\(-\dfrac 3 4 x^2 + 2 = 0\)

multiply both sides by \(-\dfrac 4 3\)

\(x^2 - \dfrac 8 3 = 0\)

and thus \(c=-\dfrac 8 3\)

well...

if you want to get fancy the best unit for expressing the depth of water is the "fathom".  It's 6 feet or 72 inches

\(253440 in = \dfrac {253440in}{72 in/fathom}=3520 fathoms\)

\(10^{-\frac 9 2} = \left(10^{-9}\right)^{\frac 1 2} =\left(\dfrac 1 {10^9}\right)^{\frac 1 2}= \dfrac 1 {\sqrt{10^9}}\)

\(E = h \nu = (2.09\times 10^{16})(6.63 \times 10^{-34})= 1.38567\times 10^{-17} \mbox{J}\)

\(\log(1.38567\times 10^{-17}) = -16.86\)

I suggest you go ask the wood chuck yourself! 

Let S be the amount of her sales for the week....and we have:

.05S + 375 = 600    subtract 375 from both sides

.05S = 225    divide both sides by ,05

S = $4500

0.0035  = 3.5 x 10^-3

1/2+1/4-1/3=    the common denominator is 12....so we have

6/12 + 3/12 - 4/12 = 5/12

No function is shown.....????