Don't you think you have to give us how much he uses per square foot?
Last week kiwi filled his 16 gallon tank with gas. On the average his car burns 0.03 gallons of gas per mile. If kiwi has 4 gallons left in the tank how many miles has he driven.... PLEASE SHOW THE ALGEBRA THE BEST YOU CAN:
16 - 4=12 gallons the car used.
12/.03=400 miles that the car drove.
400/12=33 1/3 miles per gallon-the car's milage.
Solve for X: (log(X))/(log(7))+(log(X+6))/(log(7)) = 1 Rewrite the left hand side by combining fractions. (log(X))/(log(7))+(log(X+6))/(log(7)) = (log(X)+log(X+6))/(log(7)): (log(X)+log(X+6))/(log(7)) = 1 Multiply both sides by log(7): log(X)+log(X+6) = log(7) log(X)+log(X+6) = log(X (X+6)): log(X (X+6)) = log(7) Cancel logarithms by taking exp of both sides: X (X+6) = 7 Expand out terms of the left hand side: X^2+6 X = 7 Add 9 to both sides: X^2+6 X+9 = 16 Write the left hand side as a square: (X+3)^2 = 16 Take the square root of both sides: X+3 = 4 or X+3 = -4 Subtract 3 from both sides: X = 1 or X+3 = -4 Subtract 3 from both sides: X = 1 or X = -7 (log(X))/(log(7))+(log(X+6))/(log(7)) => (log(-7))/(log(7))+(log(6-7))/(log(7)) = 1+((2 i) pi)/(log(7)) ~~ 1.+3.22892 i: So this solution is incorrect (log(X))/(log(7))+(log(X+6))/(log(7)) => (log(1))/(log(7))+(log(6+1))/(log(7)) = 1: So this solution is correct The solution is: Answer: | | X = 1
thx
-15 + 5
heres one
sorry I just saw that i used 95 not 90
the answer is
3.5 X= 132-90
3.5X = 42
divide by 3.5
X=12
one year
but how did you get 95
thank you so much
3.5X =132-95
3.5X=37
divide both sides by 3.5
x=10.57
approximate 10 1/2 months
Solve for x: x = 3 x sqrt(10-6 x) Subtract 3 x sqrt(10-6 x) from both sides: x-3 x sqrt(10-6 x) = 0 Simplify and substitute y = sqrt(10-6 x): x-3 sqrt(10-6 x) x = 5/3-5 sqrt(10-6 x)-(sqrt(10-6 x)^2)/(6)+sqrt(10-6 x)^3/2 = y^3/2-y^2/6-5 y+5/3 = 0: y^3/2-y^2/6-5 y+5/3 = 0 The left hand side factors into a product with three terms: 1/6 (3 y-1) (y^2-10) = 0 Multiply both sides by 6: (3 y-1) (y^2-10) = 0 Split into two equations: 3 y-1 = 0 or y^2-10 = 0 Add 1 to both sides: 3 y = 1 or y^2-10 = 0 Divide both sides by 3: y = 1/3 or y^2-10 = 0 Substitute back for y = sqrt(10-6 x): sqrt(10-6 x) = 1/3 or y^2-10 = 0 Raise both sides to the power of two: 10-6 x = 1/9 or y^2-10 = 0 Subtract 10 from both sides: -6 x = -89/9 or y^2-10 = 0 Divide both sides by -6: x = 89/54 or y^2-10 = 0 Add 10 to both sides: x = 89/54 or y^2 = 10 Take the square root of both sides: x = 89/54 or y = sqrt(10) or y = -sqrt(10) Substitute back for y = sqrt(10-6 x): x = 89/54 or sqrt(10-6 x) = sqrt(10) or y = -sqrt(10) Raise both sides to the power of two: x = 89/54 or 10-6 x = 10 or y = -sqrt(10) Subtract 10 from both sides: x = 89/54 or -6 x = 0 or y = -sqrt(10) Divide both sides by -6: x = 89/54 or x = 0 or y = -sqrt(10) Substitute back for y = sqrt(10-6 x): x = 89/54 or x = 0 or sqrt(10-6 x) = -sqrt(10) Raise both sides to the power of two: x = 89/54 or x = 0 or 10-6 x = 10 Subtract 10 from both sides: x = 89/54 or x = 0 or -6 x = 0 Divide both sides by -6: Answer: | | x = 89/54 or x = 0
+2-12
+3-13
and so on
x/3 =12
multiply both sides by 3
x=36
Multiply both sides by 3
x=4
1 - 1/(20e^5)
1-e^-5(.05)=0.999663103...
0.2211992169285951
yay i got that too
Let Bonnie's current age = x.....and Shelby's = 7x
And in 5 years, we have
[ x + 5 ] + [ 7x + 5 ] = 98 simplify
8x + 10 = 98 subtract 10 from both sides
8x = 88 divide both sides by 8
x = 11 = Bonnie's current age
140/3388=5/11^2=5/121
This is way easier than it seems, at first glance
Note that we can write this [ using the log property .... logab = b * log a ] as :
[2x ] * log3 3 = 14 but log3 3 is just "1".....so we can ignore it.......and we have
2x = 14 and it should be obvious that x = 7
Even my secret decoder ring fails me, here......!!!!!
[This looks like a case for Sir LA-Tex ........!!!!! ]
Although this may not be technically correct, I'm using the conversion of 1 Q = 4 cups
And the number of 1/2 cups =
[12 *4] / [1 / 4] = 192
Taking the secant inverse of (4.5600039), the angles are about 77.33° and [ 360 - 77.33]° = about 282.67°
