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Doesn't matter what number it is. All Teresa needs to do is to just walk away, quit her job, and cry in the corner for this is such an easy question...

\(\color{red}2^x=3.17\)

\(\color{lime}x=log_2(3.17)\)

\(\color{purple}x=1.6644828403646825.....\)

\(\color{cyan}e^{1.25}= 3.490342957........\)

OMG I love LaTeX! It's awesome :P

Our guest, that's the prime factorization of 28.

Factors of 28 : 1, 2, 4, 7, 14, 28.

\(\color{red}\frac{13}{sin120}=\frac{7}{sinC}\)

\(\color{lime}13sinC=7sin120\)

\(\color{blue}sinC=\frac{7sin120}{13}\)

\(\color{purple}C= asin (\frac{7sin120}{13})\)

It doesn't look like a rainbow in this color pattern...... Never mind. C approximately equals 27.79 degrees.

The 25th term: 4 + 3(25-1) = 76

d = 2r

r = \(\color{red}\frac{d}{2}\)

The program is (input)= 5 x (output) That's not hard to realize the relationship.

6 = 5 x (output)

(output) = \(\color{brown}\frac{6}{5} \)

\(\color{blue}\frac{14}{3}= 4\frac{\color{red}2}{3}\)

The remainder is 2

a(sub1)=4, d=3; a(sub25). I assume that you want the 25th term of the sequence:

1st.term=4, difference=3, 25th. term =76

Solve for b:
7.15 = 780.42 b

7.15 = 780.42 b is equivalent to 780.42 b = 7.15:
780.42 b = 7.15

Divide both sides of 780.42 b = 7.15 by 780.42:
(780.42 b)/780.42 = 7.15/780.42

780.42/780.42 = 1:
b = 7.15/780.42

7.15/780.42  =  0.00916174:
Answer: |  b = 0.00916174

The diameter of a circle is the line that passes through the center of the circle from one end of the circle to another. The radius is a line that starts from the center of the circle to the end of the circle. The radius can also calculated by the diameter divided by two. 

e^1.25= calucute value=3.490342957.............

(z1 + p1/9.8 + v1^2/2g - z2 - v2^2/2g - Hf) / 9.8 = p2

-0.3-(abs(7)-33.79-abs(12.59)) = 33.49-7+12.59=39.08

2^X=3.17

X=Log(3.17) / Log(2)

X=1.664482840..........etc.

Make a table for a function whose graph has a y-intercept of 4 and a slope of 2/3.

28=2^2 x 7

"The following table shows the percent increase of donations made on behalf of a non-profit organization for the period of 1984 to 2003. Use a graphing calculator to make a scatter plot of the data. Find an equation for and graph the line of regression. Then use the equation to predict the percent donated in the year 2015. ..."

Here's the graph and my calculation of the best-fit straight line.  

Note that in the function pc the year is relative to 2000.  For example, for the year 2015 you would just use 15.

I don't get any of the listed results for the year 2015.  

(Note that in real life it wouldn't be sensible to extrapolate so far from the measured data). 

"How to determine volume of liquid in a 50m2 area if it was 2mm thick"

2mm = 2*10^-3 m

Volume = 50*2*10^-3 m^3

Volume = 0.1 m^3

.

"There are 740 math books which are 5%of the books in the library. How many textbooks are in the library?"

Let N be the number of books in the library.

N*5/100 = 740

N = 740*100/5

N = 14800

Look up the LambertW function.  For example: http://mathworld.wolfram.com/LambertW-Function.html 

.

3h^2=512        [ /3

h^2 = 160.666...

h = √160.666...

h₁ = 13.0639452949

h₂ = - 13.0639452949

Use the sine rule

Solve for p2:       NOTE: Hf=H
0.102041 p1+(g v12)/2+z1 = H+0.102041 p2+(g v22)/2+z2

0.102041 p1+(g v12)/2+z1 = (5 p1)/49+(g v12)/2+z1 and H+0.102041 p2+(g v22)/2+z2 = H+(5 p2)/49+(g v22)/2+z2:
(5 p1)/49+(g v12)/2+z1 = H+(5 p2)/49+(g v22)/2+z2

(5 p1)/49+(g v12)/2+z1 = H+(5 p2)/49+(g v22)/2+z2 is equivalent to H+(5 p2)/49+(g v22)/2+z2 = (5 p1)/49+(g v12)/2+z1:
H+(5 p2)/49+(g v22)/2+z2 = (5 p1)/49+(g v12)/2+z1

Subtract H+(g v22)/2+z2 from both sides:
(5 p2)/49 = -H+(5 p1)/49+(g v12)/2-(g v22)/2+z1-z2

Multiply both sides by 49/5:
Answer: |  p2 = -(49 H)/5+p1+(49 g v12)/10-(49 g v22)/10+(49 z1)/5-(49 z2)/5