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aops XD

-1!  =  -(1!)  =  -(1)  =  -1

0/0 is undefined but it also is an "indeterminate expression", meaning that its value is determined by the problem that created this value. In one case, its value may be 0, in another case, its value may be 1, or -7 or pi/2, etc.

only if you ask politely

10+9=109

sorry

4/5

2(2/4)=4/4=1

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There are no variables here (ie. x) so there is nothing to solve

The cube series on the right adds up to 784. The sum on the left, before squaring, adds up to [n(n + 1) / 2]

So we get [n(n +1) / 2]^2 < 784

=> n(n + 1) / 2 < 28       Square root both sides

=> n(n + 1) < 56            Multiply by 2 to break the fraction

=> n^2 + n - 56 < 0        Rewrite

=> (n -7)(n + 8) < 0       Factor

=> n < 7, n < -8  therefore the highest integer would be 6

In case you didn't know, a sum of cubes adds up to the [n(n + 1) / 2]^2 formula we derived from squaring the left-hand sum.

Don't get confused here.  You cannot divide anything by zero. Division by zero is not defined.

--  and 0/0 is zero because the numerator is zero.

66200=20000((1 + R)^3 - 1) / R), solve for R
Solve for R:
66200 = (20000 ((R+1)^3-1))/R

66200 = (20000 ((R+1)^3-1))/R is equivalent to (20000 ((R+1)^3-1))/R = 66200:
(20000 ((R+1)^3-1))/R = 66200

Multiply both sides by R:
20000 ((R+1)^3-1) = 66200 R

Expand out terms of the left hand side:
20000 R^3+60000 R^2+60000 R = 66200 R

Subtract 66200 R from both sides:
20000 R^3+60000 R^2-6200 R = 0

The left hand side factors into a product with four terms:
200 R (10 R-1) (10 R+31) = 0

Divide both sides by 200:
R (10 R-1) (10 R+31) = 0

Split into three equations:
R = 0 or 10 R-1 = 0 or 10 R+31 = 0

Add 1 to both sides:
R = 0 or 10 R = 1 or 10 R+31 = 0

Divide both sides by 10:
R = 0 or R = 1/10 or 10 R+31 = 0

Subtract 31 from both sides:
R = 0 or R = 1/10 or 10 R = -31

Divide both sides by 10:
R = 0 or R = 1/10 or R = -31/10

(20000 ((R+1)^3-1))/R => -(20000 ((1-31/10)^3-1))/(31/10)  =  66200:
So this solution is correct

(20000 ((R+1)^3-1))/R => 20000/0 ((1+0)^3-1)  =  (undefined):
So this solution is incorrect

(20000 ((R+1)^3-1))/R => (20000 ((1+1/10)^3-1))/(1/10)  =  66200:
So this solution is correct

The solutions are:
Answer: |  R = 1/10 or R = -31/10                        R=1/10 x 100 =10%

We can solve this :

20000(1 + r)^2   + 20000(1 + r)   + 20000   = 66200     subtract  66200 from each side

20000 (1 + r)^2 + 20000 (1 + r)  - 46200     =  0         let  1 + r  = x

20000x^2 + 20000x  - 46200  = 0       divide through by 20000

x^2 + x - 231/100  =0         add 231/10  to both sides and completet the square on x

x^2 + x + 1/4 =   231/100 + 1/4      factor and simplify

(x + 1/2) ^2   =  256/100      take the positive square root of both sides

x + 1/2 =  sqrt(256/10)

x + 1/2  = 16/10

x + 1/ 2 =    8/5

x = [ 8/5 - 1/2 ]  =     11/10   = 1.1

So.....  1 + r  = 1.10      subtract 1 from both sides

r = .10   =  10%

goku can lift 40 tons with the gravity x 10   \ 40  x  10 - 400

400 x 100  x 2  x  4  x  10  x  4000  x  50 

2+2 = 4

(6+5/8)*pi = 20.8130513300323802.

I don't know you, but hi. 

Solve for a:
a^2-2 a-1 = 0

Add 1 to both sides:
a^2-2 a = 1

Add 1 to both sides:
a^2-2 a+1 = 2

Write the left hand side as a square:
(a-1)^2 = 2

Take the square root of both sides:
a-1 = sqrt(2) or a-1 = -sqrt(2)

Add 1 to both sides:
a = 1+sqrt(2) or a-1 = -sqrt(2)

Add 1 to both sides:
Answer: |  a = 1+sqrt(2)        or       a = 1-sqrt(2)

4/3*22/7*8^3*4/3*22/7*8^3 = 4603272.4172335600907029

It is NOT 21. The answer is 19.

What program? Also, you might be able to download whatever program you are talking about. If you download a program and it doesn't work or open or you have any problems, then you should give feedback to the owners or the technical assistance.

f a ship's path is mapped on a coordinate grid, it follows a straight-line path of slope 3 and passes through point (2, 5).

Part A: What is the equation of the path?

Part B: Does the ship pass through point (7, 22)?

Part C: A second ship follows a straight line, with the equation x + 3y − 6 = 0. Are these two ships sailing perpendicular to each other?

The equation of the first line is given by :

y - 5 = 3(x - 2)     simplify

y = 3x - 6 + 5

y = 3x - 1

For part B, substitute  7 for x in the equation and we have :  3(7) - 1  =  21 - 1  = 20......so......the ship passes through (7, 20), but not (7,22)

Part C......x + 3y - 6  = 0   .....rearrange this as      y = (-1/3)x + 2..........the slope of this line is the negative reciprocal of the first line, so they are perpendicular.......

No, I don't think you can.

Press "2nd" key in the top left hand corner, then you should see "cosh". Press this key, then enter your argument and close the brackets. Finally, press = sign to get your answer. Make sure the calculator in "Radians" mode, which is located in the bottom left hand corner.

P=2[1 + L] =100

P=2 + 2L =100

2L =100 - 2=98 divide both sides by 2

L =98/2

L=49, so we have:

Width = 1 unit

Length =49 units

Area = 1 x 49 =49 square units.

answer is 49

please closeth problem , I have answered it